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kodGreya [7K]
4 years ago
9

Which of the following expressions represents “thr difference of 8 and n”?

Mathematics
1 answer:
Lubov Fominskaja [6]4 years ago
7 0
The difference between 8 and n looks like,

8 - n
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You randomly choose two bills from your wallet. What is the probability that they are both $20 bills. There are two 20's, one 10
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2/6 or 33.33%

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A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.
IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car (v_0) = 40 ft/sec

Deceleration of the car (\frac{dv}{dt}) = -10 ft/sec²

Final speed of the car (v_x) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, \frac{dv}{dt}=-10\ ft/sec^2

Negative sign means the velocity is decreasing with time.

Now, \frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt}) using chain rule of differentiation. Therefore,

\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft

Therefore, the car travels a distance of 80 feet before stopping.

4 0
3 years ago
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