Question

Solve the following system of equations2x – 3y = 64x+2y=4​

Answer 1

Answer:

$\boxed{(\frac{3}{2} ,-1)}$

Step-by-step explanation:

$\left \{ {{2x-3y=6} \atop {4x+2y=4}} \right.$

It seems this system of equations would be solved easier using the elimination method (the x and y values are lined up).

Multiply everything in the first equation by -2 (we want the 4x to be able to cancel out with a -4x).

$2x-3y=6 \rightarrow -4x+6y=-12$

Now line up the equations (they are already lined up - convenient) and add them from top to bottom.

$\left \{ {{-4x+6y=-12} \atop {4x+2y=4}} \right.$

The -4x and 4x are opposites, so they cancel out.

Adding 6y and 2y gives you 8y, and adding -12 and 4 gives you -8.

$8y=-8$

Divide both sides by 8.

$y=-1$

Since you have the y-value you can substitute this in to the second (or first equation, it doesn't necessarily matter) equation.

$4x +2(-1)=4$

Simplify.

$4x -2=4$

Add 2 to both sides.

$4x=6$

Divide both sides by 4.

$x=\frac{6}{4} \rightarrow\frac{3}{2}$

The final answer is $x=\frac{3}{2} ,~y=-1$.

$(\frac{3}{2} ,-1)$