I need to answer 25 questions pls help ill give brainliest

1/2(2g-3)=-4(g+1) show work please do this ASAP

lozanna [386]

1/2(2g−3)=−4(g+1)
1/2(2g−3)=−4(g+1)
g+−3/2=−4g−4
g+−3/2+4g=−4g−4+4g5g+−32=−4
5g+−3/2+3/2=−4+3/2

5g=−5/2
5g/5=−525
g=−12

Hoped I helped!

6 0

3 years ago

Read 2 more answers

Every 3 Days Marco fills up his car with gas. Every 3 Days he washes his car. On what day will Marco fill his car and wash it.

GenaCL600 [577]

The answer is Thursday and Sunday hope this helps :D

8 0

3 years ago

Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.

igor_vitrenko [27]

Answer:

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

$m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7$

So, the solution of the equation is

$y = Ae^{m_{1} t} + Be^{m_{2} t}$

where m₁ = 3 and m₂ = -7.

So,

$y = Ae^{3t} + Be^{-7t}$

Also,

$y' = 3Ae^{3t} - 7e^{-7t}$

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

$y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1 (1)$

$y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}$

Substituting A into (1) above, we have

$\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1 \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}$

Substituting B into A, we have

$A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}$

Substituting A and B into y, we have

$y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

So the solution to the differential equation is

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

6 0

3 years ago

A(1, 3), B(5, 3), and D(1, -2) are three vertices of rectangle ABCD. The coordinates of vertex C are

harkovskaia [24]

The answer is C, (5,-2) if you graph all the other points you can easily see where the missing point should be considering it's a rectangle

6 0

3 years ago

Eric's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Eric $5.50 per pound, and type B

AlekseyPX

115.2 pounds of type A coffee were used.

<h3>What is the solution of the equation?</h3>

A mathematical statement that has an "equal to" symbol between two expressions with equal values is called an equation.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides. We have LHS = RHS (left hand side = right hand side) in every mathematical equation. To determine the value of an unknown variable that represents an unknown quantity, equations can be solved.

Let the number of pounds of type A coffee be x and the number of pounds of Type B coffee be y.

According to the question, the equations are,

5.50x + 4.40y = 762.30

x = 4y

So, the solution of the equation is obtained as follows:

5.50(4y) + 4.40y = 762.30

26.40y = 762.30

y = 762.30/26.40

y = 28.8 pounds

x = 4*28.8 = 115.2 pounds

Learn more about equations here:

brainly.com/question/2972832

#SPJ1

4 0

2 years ago