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Leokris [45]
3 years ago
15

Solve for x assume that lines wich appear to be tangent are tangent, please HELPP don't do it just for points please I really ne

ed help

Mathematics
2 answers:
andriy [413]3 years ago
6 0

Answer:

8). x = 9

9). x = 5

Step-by-step explanation:

Note that if you take a point outside a circle and take the two tangents, they are symmetrical. And if they're symmetrical, their lengths are equal!

8).

5x - 1 = 3x + 17

2x - 1 = 17

2x = 18

x = 9

9).

-4 + 4x = 3x + 1

-4 + x = 1

x = 5

snow_tiger [21]3 years ago
3 0

Answer:

Hope It Help

Step-by-step explanation:

Brainliest Please

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The lengths of the sides of a triangle are given below. Classify the triangle as acute, obtuse, or right.
abruzzese [7]

Answer:

  • A. Acute Triangle

Step-by-step explanation:

<u>Lets verify with Pythagorean:</u>

  • 17² = 289
  • 13² + 14² = 169 + 196 = 365
  • 289 < 365

The angle opposite to a greater side is less than 90° and the sum of the squares are close.

It means all three angles<u> are less than 90°</u>.

With this the triangle is <u>acute</u>.

Correct choice is A.

6 0
3 years ago
Can someone pls graph this for me ? ( just screenshot and use the marker tool to graph)
Furkat [3]
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2 years ago
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Artemon [7]
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8 0
3 years ago
Need help finding a constant k at which the function is continuous everywhere.
saveliy_v [14]

Answer:

k = -6/35

Step-by-step explanation:

To make the function continuous

kx^2 = x+k

These must be equal where the function is defined for two different intervals

This is at the point x=-6  so let x=-6

k(-6)^2 = -6+k

36k = -6+k

Subtract k from each side

36k-k = -6+k-k

35k = -6

Divide by 35

35k/35 = -6/35

k = -6/35


3 0
3 years ago
Read 2 more answers
PLEASE HELP ME QUICK!!
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