Answer:
Follows are the solution to this question:
Step-by-step explanation:
In the given question some of the data is missing so, its correct question is defined in the attached file please find it.
Let
A is quality score of A
B is quality score of B
C is quality score of C
![\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\](https://tex.z-dn.net/?f=%5Cto%20P%5BA%5D%20%3D0.55%5C%5C%5C%5C%5Cto%20P%5BB%5D%20%3D0.28%5C%5C%5C%5C%5Cto%20P%5BC%5D%20%3D0.17%5C%5C)
Let F is a value of the content so, the value is:
![\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\](https://tex.z-dn.net/?f=%5Cto%20P%5B%5Cfrac%7BF%7D%7BA%7D%5D%20%3D0.15%5C%5C%5C%5C%5Cto%20P%5B%5Cfrac%7BF%7D%7BB%7D%5D%20%3D0.12%5C%5C%5C%5C%5Cto%20P%5B%5Cfrac%7BF%7D%7BC%7D%5D%20%3D0.14%5C%5C)
Now, we calculate the tooling value:
![\to p[\frac{C}{F}]](https://tex.z-dn.net/?f=%5Cto%20p%5B%5Cfrac%7BC%7D%7BF%7D%5D)
using the baues therom:

Let's find the slope for line t first.
We can use the given points 2,6 and 10,1 to find the slope using the slope formula.

1 - 6 / 10 - 2
-5/8
The slope is -5/8.
Because we know the slope of this line, we can find the slope of the next line instantly, as they are perpendicular.
When a slope is perpendicular to another, it is equal to the negative reciprocal.
Negative reciprocal of -5/8 = 8/5
<h3>The slope of line u is 8/5</h3>
Answer:
<h2><u><em>
46 cm²</em></u></h2>
Step-by-step explanation
the figure is composed of a square with an isosceles right triangle inside, we find the area of the square and we take away the area of the triangle.
Triangle area = lxl, right-angled triangle area side by side divided by two.
8 * 8 = 64cm²
6 * 6 : 2 = 18 cm²
Area of the shaded region
64 - 18 = 46 cm²
The answer to x would be 0
Left and right side: 6.4*7=44.8
44.8+44.8=89.6
front (where the zipper is) and back: half of 5*8=20
20+20=40
40+89.6=129.6
the area of the bottom is 7*8=56
the total area is 129.6+56=185.6
I am not sure what lateral area includes. To me, the answer should be 129.6, but 129.6 is not a choice.
I'd suggest 185.6, the total surface area.