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serious [3.7K]
3 years ago
8

How to reflect a point on a unit circle across axis?

Mathematics
1 answer:
dlinn [17]3 years ago
7 0
Start at the given point. Draw a segment from that point through the center of the circle, and extend the segment until it intersects the circle. The new point of intersection of the segment and the circle is the image of the original point.
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What is the area of this figure?
Elza [17]

The bottom square portion would be 10 x 10 = 100 square inches.


The area of the triangle would be 1/2 x base x height.

The base is 10 - 6 = 4 inches.

The height is 16 -10 = 6 inches.

Area = 1/2 x 4 x 6 = 12 square inches.


Total area = 100 + 12 = 112 square inches.

6 0
3 years ago
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What two numbers multiplied equal -9 but add up to -6
jeka94
No numbers, is the question correct? Are you factoring?
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Maggie is standing in her front yard and measures the length of the shadow she casts, as well as the shadow, cast by her house.
zimovet [89]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
NEED HELP HERE ASAP<br><br> 6. Find the cube roots of 27(cos 330° + i sin 330°).
VLD [36.1K]
<span>we have that

the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]

we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

 cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

</span>z2=3[cos 230° + i sin 230°]

z3=3[cos 350° + i sin 350°]<span>

</span>
7 0
3 years ago
Solve the equation 8x-7=y-2 for x if y is 51. make sure to first solve for in terms y. x=?
Crank
X=7. if you need explanation message me
7 0
3 years ago
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