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s344n2d4d5 [400]
3 years ago
12

Resuma o tema operações com números positivos e negativos POR FAVOR RESPONDA CERTO E RÁPIDO É URGENTE!

Mathematics
1 answer:
wlad13 [49]3 years ago
3 0

Adição (+)

Positivo + Positivo = Positivo

Negativo + Negativo = Negativo

Positivo + Negativo ou Negativo + Positivo

• use o maior número e seu sinal, subtraia

Subtração (-)

Negativo - Positivo = Negativo

Positivo - Negativo = Positivo

Negativo - Negativo = Negativo + Positivo

• use o maior número e seu sinal, subtraia

Multiplicação (x)

Positivo x Positivo = Positivo

Negativo x Negativo = Positivo

Negativo x Positivo = Negativo

Positivo x Negativo = Negativo

• alterar os negativos duplos para um positivo

Divisão (÷)

Positivo ÷ Positivo = Positivo

Negativo ÷ Negativo = Positivo

Negativo ÷ Positivo = Negativo

Positivo ÷ Negativo = Negativo

• alterar os negativos duplos para um positivo

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7 0
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Suppose you can factor x^2 +bx +c as (x+p)(x+q) . If c<0, what could be the possible values of p and q?
Anna11 [10]
Ans: Option A

Explanation:
Let's solve it smartly!
Given expression: x^{2} + bx +c --- (A)
Factors: (x+p)(x+q)
Condition: c<0
Now let us expand (x+p)(x+q):
=> x^{2} + (p+q)x + pq  --- (B)

By comparing (B) with (A), we can say that:
pq = c --- (C)

Now, as the condition says, c<0, it means either p or q is negative. Both cannot be positive or both cannot be negative.

1) If p>0, q>0, it means c>0 since (+p)(+q) = (+c)(according to equation (C)). Condition is not met.
Hence, option B and D are wrong.

2) If p<0, q<0 it means c>=0 since (-p)(-q) = (+c)(according to equation (C)). Condition is not met.
Hence option C is out as well.

We are left with Option A:p<0, q>0 it means c<0 since (-p)(+q) = (-c)(according to equation (C)).
Condition is MET!
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Ans: Option A: p= -3, q= 7
4 0
3 years ago
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Answer:

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Step-by-step explanation:

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