Answer:
98, 317, 342
Step-by-step explanation:
Answer:
Quadrant III
Step-by-step explanation:
The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.
The graphs shown are of the functions:




<em>So, any linear function of the form
with
and
does not pass through Quadrant III. Answer choice 3 is correct.</em>
Hi!
<h3>To find the slope, use this formula</h3>

<h3>Put in the values</h3>

<h2>The slope is 1 </h2>
Hope this helps! :)
-Peredhel
For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

Where:
m: It is the slope of the line
b: It is the cut-off point with the y axis
We have the following points through which the line passes:

So the slope is:

Thus, the equation of the line is of the form:

We substitute one of the points and find "b":

Finally, the equation is:

Answer:

Assuming the fish pond is round, what you're given is the circumference.
So you know that 2<span>πr = 27.
We want to solve for the diameter, or d = 2r. We should isolate that.
2r = 27/</span><span>π
2r = 8.59 yards, or ~9 yards.</span>