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faltersainse [42]

3 years ago

10

To gain access to his account, a customer using an automatic teller machine (ATM) must enter a four-digit code. If repetition of

the same four digits is not allowed (for example 5555), how many possible combinations are there?

1 answer:

VMariaS [17]3 years ago

8 0

I’m not really much sure, I tried.

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I know you probably don’t see this but i forgot to do my homework it’s due tomorrow and it’s the called “Volume Unit Study Guide

saw5 [17]

Answer: Make sure all words are spelled correctly.

Try different keywords.

Try more general keywords.

Try fewer keywords.

Step-by-step explanation:

6 0

2 years ago

Rebecca has r number of crayons. Julie has 17 more crayons than Rebecca. Which expressions correctly show the number of crayons

Sedaia [141]

Answer:

I would say that it is none of the above that one is much more reasonable than the other ones

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Any one know how to find the roots of an equation?

soldier1979 [14.2K]

So what you do is
make into ax^2+bx+c=0 form

add-9/2 to both sides
y^2-2y+9/2=0
now we use the quadratice formula which is
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

ax^2+bx+c=0
1y^2-2y+9/2
a=1
b=-2
c=9/2
subsitute
x= $\frac{-(-2)+/- \sqrt{(-2)^{2}-4(1)(9/2)} }{2(1)}$
x= $\frac{2+/- \sqrt{4-(36/2)} }{2}$
x= $\frac{2+/- \sqrt{4-(18)} }{2}$
x= $\frac{2+/- \sqrt{-14} }{2}$
x= $\frac{2+/- \sqrt{-14} }{2}$
x= $1+/- \frac{\sqrt{-14} }{2}$
x= $1+/- \frac{\sqrt{14} \sqrt{-1}}{2}$
x= $1+/- \frac{\sqrt{14} i }{2}$
x= $1+/- \frac{ i \sqrt{14} }{2}$

answer is C

6 0

3 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi

stealth61 [152]

Applying our power rule gets us our first derivative,

$\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}$

simplifying a little bit,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

looking for critical points,

$\rm 0=2x^{-2/3}+4x^{1/3}$

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

$0=2x^{-2/3}\left(1+2x\right)$

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

$\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)$

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

and take our second derivative.

$\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Looking for inflection points,

$\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Again, pulling out the smaller power of x, and fractional part,

$\rm 0=-\frac43x^{-5/3}\left(1-x\right)$

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.

8 0

3 years ago

On the graph below are three points X, Y, and Z. Write the coordinates for the given dilation.

Julli [10]

ANSWER

$( - \frac{3}{2} , - 1)$

EXPLANATION

From the graph, the coordinates of Y are:

$(3,2)$

We want to find the image of this point after a dilation by a scale factor of -½ about the origin.

The rule for the dilation is :

$(x,y)\to( - \frac{1}{2} x, - \frac{1}{2} y)$

To find the coordinates of Y', we plug the coordinates of Y.

$Y(3,2)\to \: Y'( - \frac{1}{2} (3), - \frac{1}{2}(2) )$

$Y(3,2)\to \: Y'( - \frac{3}{2}, - 1)$

The first choice is correct.

6 0

3 years ago