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3 years ago

Plz help with number 1

Mathematics

1 answer:

Trava [24]3 years ago

4 0

In an isosceles triangle, the base angles are congruent. The third angle is called the vertex angle.

Here, the vertex angle is <A.

Therefore, m<C = m<B.

m<A = 3m<B + 20

m<A + m<B + m<C = 180

3m<B + 20 + m<B + m<B = 180

5m<B + 20 = 180

5m<B = 160

m<B = 32

m<C = m<B = 32

Answer: m<C = 32 deg

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In 1998, as an advertising campaign, the Nabisco Company announced a "1000 Chips Challenge," claiming that every 18-ounce bag of

Phoenix [80]

Answer:

A 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

Step-by-step explanation:

We are given that statistics students at the Air Force Academy (no kidding) purchased some randomly selected bags of cookies and counted the chocolate chips.

Some of their data are given below; 1219, 1214, 1087, 1200, 1419, 1121, 1325, 1345, 1244, 1258, 1356, 1132, 1191, 1270, 1295, 1135.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of chocolate chips = $\frac{\sum X}{n}$ = 1238.2

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 94.3

n = sample of car drivers = 16

$\mu$ = population mean number of chips in a bag

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $1238.2-2.131 \times {\frac{94.3}{\sqrt{16} } }$ , $1238.2+2.131 \times {\frac{94.3}{\sqrt{16} } }$ ]

= [1187.96, 1288.44]

Therefore, a 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

7 0

3 years ago

As an incoming college freshman, Tina received a 10-year $9,900 Federal Direct

Ksju [112]

The amount charged on the loan which is the loan interest rate, increases as the time after the initial amount is credited into the account increases.

The interest on the Federal Direct Unsubsidized Loan after 4 years 6 months is $1,911.195

Reasons:

The given parameter are;

Loan amount, the principal, P = $9,900

Duration of the loan = 10 years

Loan interest rate, R = 4.29%

Required:

The amount of interest that will accrue while she is still in school and over the 6-months grace period for the freshman loan.

Solution:

Based on a similar question on an online source, we have;

Interest, I = P × R × T

Where;

T = The time = The time the freshman is in school + 6 months

Therefore, normally, we have;

T = 4 years + 6 months = 4.5 years

R = 4.29% = 0.0429

Therefore;

Interest, I = 9,900 × 0.0429 × 4.5 = 1911.195

The interest that will accrue while she is still in school and over the 6-months grace period for the loan, I = $1,911.195

Learn more about the interest rate here:

brainly.com/question/1368015

6 0

2 years ago

(a^2-4)(9-b^2)+24ab

Sholpan [36]

-a2b2 + 9a2 + 24ab + 4b2 - 36 hope it helps

7 0

3 years ago

If the area of the rectangle below is 36 square yards, what is the length of the missing side? Don’t forget to include the unit

Vitek1552 [10]

Answer: wheres the picture

Step-by-step explanation:

5 0

3 years ago

Suppose the line of best fit is being found for some points that have an r-value of 0.769. If the standard deviation of the x-co

jeyben [28]

r value i.e Correlation between x value and y value = 0.769

$A_{x}$ =Standard deviation of the x-coordinate = 5.508

$A_{y}$ =Standard deviation of the y-coordinate = ?=k

Slope of line is given by formula

If slope of line is m, then

m = $r\times \frac{ A_{x}}{A _{y}}$

m= $0.769 \times \frac{k}{5.508}$

Substitute the value of k, i.e Standard deviation of the y-coordinate and then you can get the slope of line to three decimal places.

7 0

3 years ago