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mr_godi [17]
3 years ago
13

If p+q+r = 1 and pq+qr+pr = -1, and pqr = -1, find the value of 

D%2B%20r%5E%7B3%7D%20%20%20" id="TexFormula1" title=" p^{3}+ q^{3}+ r^{3} " alt=" p^{3}+ q^{3}+ r^{3} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Ugo [173]3 years ago
6 0
Pq+qr+pr= pqr (because they are both equal to -1)
then you divide both sides by p to get
q+ qr/p + r = qr. then you divide both sides by q and get
r/p + r/q = r. so I divided both sides by r to get
P + q =0 therefore p= -q. putting that into the first equation allows you to get that r=1 because p and q cancel each other out. then I put that into pq+qr+pr=-1 so pq+q+p=-1 since p=-q the q+p gets canceled out and you're left with pq=-1 and since it is the product of the two numbers and q is the negative of p. q=-1 while p=1. therefore p=1 r=1 and q=-1
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Morgarella [4.7K]

Answer:

I hope it helps u

Step-by-step explanation:

Let's solve your system by elimination.

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6 0
2 years ago
The product of two numbers is 240. The first number is 8 less than the second number. Write an equation can be used to find x
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Answer:

The equation x = y-8

The equation  (y-8) y = 240

The first number x = 12 and second number y =20

Step-by-step explanation:

<u>Explanation</u>:-

<u>Step(l)</u>:-

Let 'x' be the first number and 'y' be the second number

Given the product of two numbers is 240

Given  data        x y = 240 …(l)

Given data the first number is 8 less than the second number.

                       x = y-8...(ll)

Substitute (ll) in equation (l) , we get

                           (y-8) y = 240

                           y^{2} -8y -240 =0

                            y^{2} -20y+12y -240 =0

                           y(y -20)+12(y -20) =0

                           (y +12)(y -20) =0

                          y = -12 and y = 20

              Y= -12 is not satisfied

              we can choose y = 20

<u>Step(ll):</u>-

Given data x =y-8

  substitute value y = 20 in x = y -8

                                             x = 20-8 = 12

<u>Final answer</u>:-

The first number x = 12 and second number y =20

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