Question

If p+q+r = 1 and pq+qr+pr = -1, and pqr = -1, find the value of D%2B%20r%5E%7B3%7D%20%20%20" id="TexFormula1" title=" p^{3}+ q^{3}+ r^{3} " alt=" p^{3}+ q^{3}+ r^{3} " align="absmiddle" class="latex-formula">

Answer 1

Pq+qr+pr= pqr (because they are both equal to -1)
then you divide both sides by p to get
q+ qr/p + r = qr. then you divide both sides by q and get
r/p + r/q = r. so I divided both sides by r to get
P + q =0 therefore p= -q. putting that into the first equation allows you to get that r=1 because p and q cancel each other out. then I put that into pq+qr+pr=-1 so pq+q+p=-1 since p=-q the q+p gets canceled out and you're left with pq=-1 and since it is the product of the two numbers and q is the negative of p. q=-1 while p=1. therefore p=1 r=1 and q=-1