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lina2011 [118]
3 years ago
5

Multiple Choice

Computers and Technology
1 answer:
Maurinko [17]3 years ago
8 0

Answer:

dont do more then you handle

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Câu 4. Trong môi trường lập trình CodeBlocks phím F9 dùng để: A. Biên dịch chương trình B. Chạy chương trình C. Soạn thảo chương
Debora [2.8K]

Answer:

câu trả lời là c nha

Explanation:

7 0
3 years ago
Does this mean that the radius is the input aka 3 ? what about the PI ?
strojnjashka [21]

Explanation:

In  this question

d is known as diameter

r is known as radius

c is known as circumference

pi is known as π

a is known as area

Now, In Maths

Area of circle = π×r×r

Circumference of circle = 2×π×r

Radius (r) = diameter(d)÷2

Given diameter is 6

then, r = 6 ÷2

r = 3

so, diameter = 6

radius = 3

circumference = 2×π×r

                        = 2×3.14×3 ( the value of π is equal to 3.14)

                        = 18.84

Area = π×r×r

= 3.14×3×3 ( the value of π is equal to 3.14)

 = 28.26

6 0
3 years ago
According to peacemaking criminology, our society denying a citizen's basic rights is another dimension of
katovenus [111]

Answer:

Violence.

Explanation:

Peacemaking criminology believes that our justice system it's just using a different form of violence to deal with violence.

This movement states that we need to re-enter violent individuals into society, and sees crime as a direct result of a determinate social structure, such as extreme poverty, violent environments, racial hate, etc.

4 0
3 years ago
Read 2 more answers
Assume that you have been hired by a small veterinary practice to help them prepare a contingency planning document. The practic
nikdorinn [45]

Answer:

Answer explained below

Explanation:

Given: The information provided is given as follows:

  • There is a small veterinary practice which includes the services like office visits, surgery, hospitalization and boarding.
  • The clinic only has a small LAN, four computers and internet access.
  • The clinic only accepts cats and dogs.
  • Hurricanes are the major threatening factor in the geographical region where the clinic is located.
  • The clinic is established in a one-story building with no windows and meet all the codes related to hurricanes.
  • As public shelters do not allow animals to stay when there is a possibility of hurricanes, therefore the clinic does not accept animals for boarding during that time

Contingency planning documents for the tasks given is as follows:

  1. Threat category along with their business impact:
  • Hurricane: It is given that the region where the clinic is located is highly threatened by hurricanes. This type of disaster can affect the life of the employees as well as patients present in the building. Also, in case of a strong hurricane, the building can also be damaged.
  • Preventive measures: Separate shelters can be installed for animals in case of emergency.

  • Fire: In case of fire due to malfunctioning of any electrical equipment or any other reason, there is no window or emergency exit available. It can damage the building and the life of the employees and animals will be in danger.
  • Preventive measures: Services should be provided to all the electrical equipment’s from time to time and emergency exits should be constructed so that there is a way to get out of the building in case the main entrance is blocked due to any reason in the time of emergency.

  • Viral Influenza: If an employee or animal is suffering from any serious viral disease. That viral infection can easily spread to others and make other animals as well as employees sick. If the employees working in the clinic are sick. This will highly affect the efficiency of them which will then affect the business.
  • Preventive measures: This can be avoided by giving necessary vaccines to the employees from time to time and taking care of the hygiene of the patient as well as the clinic which will make the chance of infection to spread low.

  • Flood: In case of a flood like situation, as given the building has only one story and there is no emergency exit for employees and animals to escape. This can put the life of the employees and animals in danger and can affect the working of the clinic as well.
  • Preventive measures: This can be prevented by collecting funds and increasing the story’s in the building or constructing alternate site location so that in case of emergency, the animals or employees can be shifted to other locations.
4 0
4 years ago
g 1. Write a program that asks the user for a number greater than 5 and prints all values between 1 and n that are multiples of
a_sh-v [17]

PROGRAM 1

#include <iostream>  

using namespace std;

int main() {

   int n;

   // user input taken for n

   cout<<"Enter any number greater than five: ";

   cin>>n;

   

   cout<<"The multiples of 5 between 1 to "<<n<<" are shown below."<<endl;

   

   // displaying multiples of 5 between 1 to n

   for(int h=1; h<=n; h++)

   {

       // if number is completely divisible by 5, remainder will be 0

       if( (h%5)==0)

           cout<<h<<endl;

   }

 

   return 0;

}

OUTPUT

Enter any number greater than five: 22

The multiples of 5 between 1 to 22 are shown below.

5

10

15

20

The program does not implements any input validation since this is not mentioned in the question.

User input is taken. All the multiples of 5 computed inside a for loop, and displayed to the console.

PROGRAM 2

#include <iostream>

using namespace std;

int main() {

   // variables to hold respective values

   int n;

   int sum=0;

   double avg=0;

   

   do

   {

       // user input taken for n

       cout<<"Enter any number between 1 and 100: ";

       cin>>n;

       if(n<1 || n>100)

           cout<<"Invalid number. Enter valid number."<<endl;

       cout<<""<<endl;

       

   }while(n<1 || n>100);

   

   // computing sum and average of numbers from 1 to n

   for(int h=1; h<=n; h++)

   {

       sum = sum+h;

   }

   

   avg=avg+(sum/n);

   

   cout<<"Sum of all the numbers from 1 to "<<n<<" is "<<sum<<endl;

   

   cout<<""<<endl;

   cout<<"Average of all the numbers from 1 to "<<n<<" is "<<avg<<endl;

   

   return 0;

}

OUTPUT

Enter any number between 1 and 100: 111

Invalid number. Enter valid number.

Enter any number between 1 and 100: 0

Invalid number. Enter valid number.

Enter any number between 1 and 100: 23

Sum of all the numbers from 1 to 23 is 276

Average of all the numbers from 1 to 23 is 12

The program not implements any input validation since this is mentioned in the question.

User input is taken inside do-while loop till valid input is obtained.

The sum of all numbers from 1 to n computed inside a for loop, average computed outside for loop.

Both values are displayed to the console.

5 0
3 years ago
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