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katen-ka-za [31]
3 years ago
12

What is the name given to the amount that a particular camera’s lens opens?

Computers and Technology
1 answer:
RSB [31]3 years ago
7 0

Answer:

The correct answer to the following question will be "Aperture".

Explanation:

  • An Aperture is an opening or a hole by which light passes. More primarily, an optical system's aperture and focal length determine a package of rays cone angle that reaches a focus throughout the image plane.
  • Aperture is also the name given to the volume that the lens of a given camera opens.
  • In other contexts, the word aperture can also be used to indicate a system that blocks light outside of a given region. For example, in astronomy, a photometric aperture around a star typically correlates to a circular window across the picture of a star under which the intensity of light is assumed.

The other three options will not be the answer of the given question because, ISO (The ISO is an international standard-setting body consisting of members from different organizations and national standards), Resolution (the level of determination) and Shutter speed (the time frame the film or digital sensor is exposed to light inside of the camera when a camera shutter is open while taking a photo).

So, Aperture is the right answer.

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A. ampersand

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What is 8 hours, 5 minutes, 22 seconds minus (-) 7 hours, 24 minutes, 37 seconds?
olga_2 [115]

Answer:

Enter time 1 HH:MM:SS8:5:22                                                                                                    

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Explanation:

The program for above in Python is:

from datetime import datetime

s1 = input("Enter time 1 HH:MM:SS")

s2 = input("Enter time 2 HH:MM:SS")

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print(tdiff)

We are using the datetime class in datetime module for using strptime to find the difference between the two times.

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4 years ago
An information- and communication-based electronic exchange environment mostly occupied by sophisticated computer and telecommun
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Answer: 8.1 msec.

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If we are told that we have a transmission link of sending 10 Mbits in one second, setting up a direct proportion, we can find out how much time is needed to send 4096 bits along the same channel, as follows:

10⁶ bits = 1 sec

4096 bits = x  ⇒ x = 4096 bits. 1 sec / 10⁶ bits = 4.1 msec.

As we have 4 msec of latency between sender and the receiver, we need to add these 4 msec to the transit time, so we have a total message transmission time of 8.1 msec.

8 0
3 years ago
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