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Schach [20]
3 years ago
13

Use the given values of n and p to find the minimum usual value μ − 2σ and the

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0
The answer to this question is 39.28; 65.12
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How to factor by grouping: <br><img src="https://tex.z-dn.net/?f=%7B27x%7D%5E%7B3%7D%20%20-%2075x" id="TexFormula1" title="{27x}
Nataly [62]

Answer:

3 x (3 x - 5) (3 x + 5)

Step-by-step explanation:

Factor the following:

27 x^3 - 75 x

Factor 3 x out of 27 x^3 - 75 x:

3 x (9 x^2 - 25)

9 x^2 - 25 = (3 x)^2 - 5^2:

3 x (3 x)^2 - 5^2

Factor the difference of two squares. (3 x)^2 - 5^2 = (3 x - 5) (3 x + 5):

Answer: 3 x (3 x - 5) (3 x + 5)

5 0
3 years ago
Find the domain of the rational function 9x/(x+5)(x+3)
xenn [34]

Answer:

the domain is : D = ]-∞ , -5[ U ]-5 , -3[ U ]-3 , +∞[

Step-by-step explanation:

hello :

f(x) = 9x/(x+5)(x+3)

f exist for : (x+5)(x+3) ≠ 0

(x+5)(x+3)=0

x+5=0 or x+3=0  means : x= - 5 or x= -3

the domain is : D = ]-∞ , -5[ U ]-5 , -3[ U ]-3 , +∞[

7 0
3 years ago
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
3 years ago
Write three items that a fraction can represent.
natka813 [3]
The first thing that fraction can  can represent is Pizza, pie,and onions. Because you can cut the pizza, the pie, and the onion into different or equal spaces. Hoped it helped.
6 0
3 years ago
Read 2 more answers
I need help!!!!!! I dont know what else to put in here
skad [1K]

The answer is D. Quadrant I, as both the X and Y coordinates are positive.

5 0
3 years ago
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