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Lubov Fominskaja [6]
3 years ago
10

What are there two solutions for the equations |6+y|=2?Explain.

Mathematics
2 answers:
tester [92]3 years ago
7 0

Because the equation is a positive number lower than the original

Lady bird [3.3K]3 years ago
6 0

Answer:

y= -4

Step-by-step explanation:

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Find the x-intercepts (if any) for the graph of the quadratic function.
OleMash [197]
Here is the answer but basically the work you just plug in 6 for A, 12 for B, and 5 for C..into the quadratic formula and solve from there

8 0
3 years ago
A thermometer shows a temperature of Negative 20 and three-fourths degrees. A chemist recorded this temperature in her notebook
fredd [130]

Answer:

The answer is C.

Step-by-step explanation:

3/4 is equal to 0.75. If you combine 0.75 with -20, then it is 20.75.

4 0
3 years ago
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Select all possible values for x in the equation x^3=375?
Helga [31]
<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

<h2>Why?</h2>

To solve the problem, we need to remember the following properties of the exponents and roots:

a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}

Then, we are given the expression:

x^{3}=375

So, finding "x", we have:

x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}

Hence, the possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

Have a nice day!

7 0
3 years ago
The midpoint of AB is M(0, 3) If the coordinates of A are (4, - 1) , what are the coordinates of B?
Harlamova29_29 [7]

-4;4

XB=0*2-4

YB=3*2-(-1)

3 0
2 years ago
Whats the lcm of 8 and 10
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The answer is 40. Hope this helped! Between 8 and 10, you can determine the least common multiple by multiplying. 8*5=40, and 10*4=40.
6 0
3 years ago
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