What is the square root of 11 over the square root of 3?

Mathematics

1 answer:

blsea [12.9K]2 years ago

6 0

11÷3= 3.666666667

Square root it. √3.666666667= 1.914854216

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(x5 + y5) ÷ (x + y) please answer ASAP

Shkiper50 [21]

Answer:

$\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4$

Step-by-step explanation:

Given the expression

$\left(x^5+y^5\right)\div \left(x+y\right)$

$\mathrm{Apply\:factoring\:rule:\:}x^n+y^n=\left(x+y\right)\left(x^{n-1}-x^{n-2}y+\:\dots \:-\:xy^{n-2}\:+\:y^{n-1}\right)\:\quad \quad \mathrm{n\:is\:odd}$

$x^5+y^5=\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)$

$=\frac{\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)}{x+y}$

Cancel the common factor: x+y

$=x^4-x^3y+x^2y^2-xy^3+y^4$

Thus,

$\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4$

3 0

2 years ago

Given f(x) = 3x + 4 and g(x) = 8x + 1<br> then what is ( f + g )(0))?<br><br> *****HELP*^^^^^^

pochemuha

• f(x) = 3x + 4

• g(x) = 8x + 1

Sum both functions above:

(f + g)(x) = f(x) + g(x)

(f + g)(x) = (3x + 4) + (8x + 1)

(f + g)(x) = 3x + 8x + 4 + 1

(f + g)(x) = 11x + 5

Therefore,

(f + g)(0) = 11 · 0 + 5

(f + g)(0) = 0 + 5

(f + g)(0) = 5 <——— this is the answer.

I hope this helps! =)

3 0

2 years ago

Parabola passes through the points (0,5), (1,4), and (2,5). What function does the graph represent?

AfilCa [17]

Answer:

x^2 - 2x + 5 = 0.

Step-by-step explanation:

The (0, 5) is the point where the parabola passes through the y axis (where x = 0), so we can write the equation as

y = ax^2 + bx + 5 where a and b are constants to be found.

Also, since (1, 4) and (2, 5) are points on the curve, substituting, we have the system:

a(1)^2 + 1b + 5 = 4

a(2)^2 + 2b + 5 = 5