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Harlamova29_29 [7]

3 years ago

7

Please someone know this ?

1 answer:

sladkih [1.3K]3 years ago

3 0

Answer:

sas fact congruency

Step-by-step explanation:

angle and same side are given

both triangle have same side

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What are the next 3 numbers in this pattern of integers -2, -1, -1, 0, -1, 1, -2

sashaice [31]

Answer:

The next 3 numbers to the given pattern of integers is -2,-1,-1,0,-1,1,-2 are 3,-5,8

Step-by-step explanation:

Given pattern of integers is -2,-1,-1,0,-1,1,-2

To find their next 3 numbers of the given pattern :

Let $a_{1}=-2$

$a_{2}=-1$

$a_{3}=a_{1}-a_{2}$

$=-2-(-1)$

$=-2+1$

Therefore $a_{3}=-1$

$a_{4}=a_{2}-a_{3}$

$=-1-(-1)$

$=-1+1$

Therefore $a_{4}=0$

Similarly we have $a_{5}=-1$ , $a_{6}=1$ , $a_{7}=-2$

The general form to the given pattern is

$a_{n}=a_{n-2}+a_{n-1}$ for $n={\{1,2,3,4,5,6,7,8,9,10}\}$

Therefore to find the $a_{8},a_{9},a_{10}$

Put n=8 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{8}=a_{8-2}-a_{8-1}$

$=a_{6}-a_{7}$

$=1-(-2)$

$a_{8}=3$

Put n=9 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{9}=a_{9-2}-a_{9-1}$

$=a_{7}-a_{8}$

$=-2-(3)$

$a_{9}=-5$

Put n=10 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{10}=a_{10-2}-a_{10-1}$

$=a_{8}-a_{9}$

$=3-(-5)$

$a_{10}=8$

Therefore the next 3 numbers are 3,-5,8

4 0

3 years ago

How I writing this in a expresión

Anon25 [30]

Answer:

2.75x+122.5

Step-by-step explanation:

Horse=x

Stork=x+70

Whale=3/4(x+70) = 0.75(x+70) = 0.75x+52.5

x+x=70+0.75x+52.5

2.75x+122.5

4 0

3 years ago

Read 2 more answers

Question: x-10<6-5x<br><br> is it <br><br> x<8/3<br><br> OR<br><br> x<-8/3<br><br> help ;-;

Montano1993 [528]

You need to isolate/get x by itself in the inequality:

x - 10 < 6 - 5x Add 5x on both sides

x + 5x - 10 < 6 - 5x + 5x

6x - 10 < 6 Add 10 on both sides

6x - 10 + 10 < 6 + 10

6x < 16 Divide 6 on both sides to get x by itself

$x$ Simplify the fraction

$x$ So the 1st option

7 0

3 years ago

If 6m + 4 = 8m, then 4m =<br> a. 6<br> b. 2<br> c. 4<br> d. 8

Over [174]

Answer:

here is your correct answer dude

5 0

3 years ago

Read 2 more answers

Tell whether the given side lengths form a right triangle.<br> 6, 11, 16

Lubov Fominskaja [6]

Given:

The lengths of the sides of a triangle are 6, 11, 16.

To find:

Whether the given triangles is a right angle triangle or not.

Solution:

Pythagoras theorem:

$Hypotenuse^2=Perpendicular^2+Base^2$

A triangle is a right angle triangle if the sum of squares of two smaller sides is equal to the square of the largest sides.

In the given triangle the length of the largest side is 16.

Square of the largest sides is:

$16^2=256$

Sum of the squares of the two smaller sides is:

$6^2+11^2=36+121$

$6^2+11^2=157$

Since $6^2+11^2\neq 16^2$ , therefore the given triangle is not a right angle triangle.

5 0

3 years ago