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Julli [10]
3 years ago
11

Could you Solve. 21r<7​

Mathematics
2 answers:
Sphinxa [80]3 years ago
8 0

Yes, I can solve that inequality.

Any value of ' r ' that's less than 1/3 is a solution.

Likurg_2 [28]3 years ago
3 0

Answer:

r < 1/3

Step-by-step explanation:

21r<7

Divide each side by 21

21r/21<7/21

r < 1/3

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Problem PageQuestion An automobile manufacturing plant produced 34 vehicles today: 16 were motorcycles, 9 were trucks, and 9 wer
8_murik_8 [283]

Answer:

Probability that the first vehicle selected is a motorcycle and the second vehicle is a van is (24/187) or 0.1283.

Step-by-step explanation:

We are given that an automobile manufacturing plant produced 34 vehicles today: 16 were motorcycles, 9 were trucks, and 9 were vans.

Plant managers are going to select two of these vehicles for a thorough inspection. The first vehicle will be selected at random, and then the second vehicle will be selected at random from the remaining vehicles.

As we know that, <u>Probability of any event</u>  =  \frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}

<u>Now, Probability that the first vehicle selected is a motorcycle is given by;</u>

                   =  \frac{\text{Number of motorcycles}}{\text{Total number of vehicles}}

Here, Number of motorcycles = 16

Total number of vehicles = 16 + 9 + 9 = 34

So, <em>Probability that the first vehicle selected is a motorcycle</em> =  \frac{16}{34}

<u>Similarly, Probability that the second vehicle is a van is given by;</u>

              =   \frac{\text{Number of vans}}{\text{Total number of remaining vehicles}}

Here, Number of vans = 9

And Total number of remaining vehicles after selecting one motorcycle = 34 - 1 = 33

So,<em> Probability that the second vehicle selected is a van</em> =  \frac{9}{33}

Therefore, the probability that the first vehicle selected is a motorcycle and the second vehicle is a van  =  \frac{16}{34}\times \frac{9}{33}

                                               =  \frac{24}{187}  =  <u>0.1283</u>

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3 years ago
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Answer:

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