Answer:
404 cm³ Anyway... Look down here for my explanation.
Step-by-step explanation:
Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.
We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)
44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°
The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.
Shaded area 88.8/360*area of circle - ½*7*788.8°
= 88.8/360*π*7² - 24.5*sin 88.8°
13.5 cm²
(using area of ∆ = ½.a.b.sin C for the triangle)
Volume of water = cross-sectional area * length
13.5 * 30 cm³
404 cm³
Answer:
Infinity Many
Step-by-step explanation:
x can pretty much be any number possible. It will just equal something different every time.
Answer:
Height of building from base to ladder = 5.8 meter (Approx.)
Step-by-step explanation:
Given:
Length of ladder = 6 meters
Distance of ladder from base = 1.5 meters
Find:
Height of building from base to ladder
Computation:
Perpendicular = √Hypotenuse² - Base²
Height of building from base to ladder = √Length of ladder² - Distance of ladder from base²
Height of building from base to ladder = √6² - 1.5²
Height of building from base to ladder = √36 - 2.25
Height of building from base to ladder = √33.75
Height of building from base to ladder = 5.8 meter (Approx.)
The formula
a(n) = 2 - 5(n-1)
is in the form
a(n) = a1 + d(n-1)
where
a1 = first term = 2
d = -5 = common difference
The first term is carried over to the recursive formula. We start with a1 = 2. The next term after that is found by subtracting 5 from the previous term. So
second term = (first term) - 5
third term = (second term) - 5
and so on
The recursive step would be
a(n) = a(n-1)-5
So that's why the answer is choice C
