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4 years ago

Oomygawd plz help me with this math hw

Mathematics

1 answer:

aev [14]4 years ago

6 0

Hi There!

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Slope Intercept Form: y = mx + b

Where: m = slope and b = y-intercept

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Question 11: The slope being 0.5 is the pay for the amount of miles he pays daily.

Question 12: y = 2x + 20

Question 13: y = 25x + 50

Question 14: y = 1/2x + 6

Question 15: y = 2x + 15

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Hope This Helps :)

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A boat traveled 30 miles upstream on a river in 6 hours. The return trip took the boat 3 hours. What was the rate of the river c

Natasha_Volkova [10]

Answer:

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Step-by-step explanation:

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6 0

3 years ago

he measures of the angles of a triangle are (2x), (x + 14), and (x - 38). Determine the value of x and the measures of each of t

Olenka [21]

Answer:

Value of x:

x = 1

Values of Each Side:

(2x) Measure = 102

(x + 14) Measure = 65

(x - 38) Measure = 13

Step-by-step explanation:

We know that the measures of a triangle always add up to 180.

So to solve, we use the equation: (2x) + (x + 14) + (x - 38) = 180. To solve, first first combine like terms to get: 4x - 24 = 180. Now add 24 to both sides to get: 4x = 204. Now divide 4 from both sides to get: x = 51.

Now insert 51 for x in all the angles to get the final measures.

Hope it helps!

3 0

3 years ago

Use the empirical rule to solve the problem. The annual precipitation for one city is normally distributed with a mean of 288 in

nadezda [96]

Answer:

$z=-1.99$

$z=1.99$

And if we solve for a we got

$a=288 -1.99*3.7=214.4$

$a=288 +1.99*3.7=295.4$

And the limits for this case are: (214.4; 295.4)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the annual precipitation of a population, and for this case we know the distribution for X is given by:

$X \sim N(288,3.7)$

Where $\mu=288$ and $\sigma=3.7$

The confidence level is 95.44 and the signficance is $1-0.9544=0.0456$ and the value of $\alpha/2 =0.0228$ . And the critical value for this case is $z = \pm 1.99$