<u>Answer:</u> The volume when the pressure and temperature has changed is 
<u>Explanation:</u>
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
Let us assume:
![P_1=1.20atm\\V_1=795mL\\T_1=116^oC=[116+273]K=389K\\P_2=0.55atm\\V_2=?mL\\T_2=75^oC=[75+273]K=348K](https://tex.z-dn.net/?f=P_1%3D1.20atm%5C%5CV_1%3D795mL%5C%5CT_1%3D116%5EoC%3D%5B116%2B273%5DK%3D389K%5C%5CP_2%3D0.55atm%5C%5CV_2%3D%3FmL%5C%5CT_2%3D75%5EoC%3D%5B75%2B273%5DK%3D348K)
Putting values in above equation, we get:
Hence, the volume when the pressure and temperature has changed is
Explanation:
SADMEP
-2(bx-5) = 16 distribute
-2bx +10 = 16 subtracte
-10 -10
-2bx = 6
divide by -2x (on both sides)
b = -3x
Answer:
option B
cementation and compaction
This correct option is C.
10^-2 = 0.001
8.7 * 10^-2 = 8.7 * 0.001 = 0.0087
Thus, 8.7 * 10^-2 is equivalent to 0.0087.
Answer:
To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest
