Answer:
TRUE!!!!
Explanation:
Water can act as both an acid and a base in solution and undergoes autoionization, where it can be both an acid and a base to itself. When mixed with an acid, water accepts hydrogen ions and acts as a base. However, when water is mixed with a base, it donates hydrogen ions and acts like an acid.
Not my words! I hope this helps :)
your answer is 0.00833M the volume was converted into liters
NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)
Using the molarity equation, we can find the number of moles of HCl that reacted:
molarity=mol soluteL soln
mol solute=(molarity)(L soln)
mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl
(volume converted to liters)
Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:
0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH
Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:
molarity=mol soluteL soln
Answer:
It accepted a proton from HCl
Explanation:
When properly written, the equation box the reaction is given as; HCl(aq) + H2O(l) ----> H3O+(aq) + Cl-(aq).
According to Brownstead-Lowry definition of acids and bases, an acid donates protons while a base accepts protons.
Water molecule acts as a base in the reaction because it accepted a proton from HCl in the reaction above.
(anode +) Cu⁰(s) - 2e⁻ → Cu²⁺(aq)
