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Sauron [17]
3 years ago
5

A quantity of gas was cooled from 323 K to 273 K. Express this temperature

Chemistry
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

give more details

Explanation:

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Provide a balanced molecular equation, total ionic, and net ionic equation for sodium phosphate and zinc acetate.
vivado [14]

Answer: Balanced molecular equation :

2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)

Total ionic equation:

6Na^+(aq)+3PO_4^{2-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)  

The net ionic equation:

2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)

Explanation:

Complete ionic equation : In complete ionic equation, all the substances that are strong electrolyte are present in an aqueous state as ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When sodium phosphate and zinc acetate then it gives zinc phosphate and sodium acetate as  product.

The balanced molecular equation will be,

2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)

The total ionic equation in separated aqueous solution will be,

6Na^+(aq)+2PO_4^{3-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)

In this equation, and  are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)

5 0
3 years ago
Which carbon skeleton represents a ketone?
julsineya [31]

Yo sup??

The correct answer is option C

the rest are aldehyde, carboxylic acid and ether respectively.

Hope this helps.

5 0
3 years ago
Read 2 more answers
What is the mole fraction of oxygen in a gaseous mixture containing 25 grams of oxygen, 15 grams of nitrogen, and 10 grams of he
4vir4ik [10]
Convert all the gases from grams to moles using their molar masses first. Remember that nitrogen and oxygen exist as DIATOMIC gases.

O2 - 25 g / 32 g/mol = 0.78 mol O2
N2 - 15 g / 28.02 g/mol = 0.54 mol N2
He - 10 g / 4.0 g/mol = 2.5 mol He

Add all the moles of gases.

0.78 + 0.54 + 2.5 = 3.82 moles

Divide O2 moles by total moles.

0.78/3.82 = 0.20
7 0
3 years ago
Identify the precipitate in this reaction: calcium nitrate reacts with sodium phosphate.
Marat540 [252]
3Ca(NO₃)₂(aq) + 2Na₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6NaNO₃(aq)

3Ca²⁺ + 6NO₃⁻ + 6Na⁺ + 2PO₄³⁻ → Ca₃(PO₄)₂ + 6Na⁺ + 6NO₃⁻

3Ca²⁺ + 2PO₄³⁻ → Ca₃(PO₄)₂  (calcium phosphate is the precipitate)
8 0
3 years ago
How many milliliters of an aqueous solution of 0.238 M iron(III) chloride is needed to obtain 18.8 grams of the salt?
avanturin [10]

Explanation:

Salt?%$- RICE BUTTRESS Ê TCHAIKOVSKY

7 0
3 years ago
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