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lukranit [14]
3 years ago
9

How to calculate the frequency of an ion

Chemistry
1 answer:
sergij07 [2.7K]3 years ago
8 0

solution:

You need to find the frequency, and they have already given you the wavelength. And since you already know the speed of light, you can use formula (2) to answer this problem. Remember to convert the nano meters to meters because the speed of light is in meters. (1 nm = 1.0 x 10^{-9} m)

v=c\lambda \\v= (3.00 \times 10^8 m/s)/(6.9\times 10^-7 m) \\v = 4.35 \times 10^{14} s^{-1}

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what noble gas has the same electron configuration as each of the ions in the following compounds? a. Cesium sulfide b. strontiu
saveliy_v [14]

Answer:

A. Cesium sulfide

Explanation:

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7 0
3 years ago
Magnesium reacts very slowly to form magnesium hydroxide and hydrogen gas. Write a word amd chemical equation for this reaction.
Varvara68 [4.7K]

Answer: -

Magnesium reacts very slowly to form magnesium hydroxide and hydrogen gas. The balanced chemical equation for the reaction is

Mg + 2H₂O → Mg(OH)₂ + H₂

Explanation: -

Chemical symbol of magnesium = Mg

Chemical formula for magnesium hydroxide = Mg(OH)₂

Chemical formula for hydrogen gas = H₂

The other reactant with Mg must be water H₂O.

Thus the balanced chemical equation for the reaction is

Mg + 2H₂O → Mg(OH)₂ + H₂

7 0
3 years ago
The length breadth and thickness of a brick is 18cm 8 cm and 5cm respictively find the area of the widest part of rhe brick​
Sunny_sXe [5.5K]

Answer:

144cm²

Explanation:

Given dimensions:

     Length x breadth x thickness

        18cm  x   8cm    x    5cm

The widest part of this figure will be the face containing the length and the breadth.

The breadth is the width of the figure;

Area of the widest part  = length x breadth = 18cm x 8cm  = 144cm

The area of the widest part of the figure is 144cm²

4 0
3 years ago
A gas occupies 100 mL at 150. kPa. Find its volume at 200. kPa. You must show all your work to receive credit. Be sure to identi
PtichkaEL [24]

The Boyle-Mariotte's law or Boyle's law is one of the laws of gases that <u>relates the volume (V) and pressure (P) of a certain amount of gas maintained at constant temperature</u>, as follows:

PV = k

where k is a constant.

We can relate the state of a gas at a specific pressure and volume to another state in which the same gas is at different P and V since the product of both variables is equal to a constant, according to the Boyle's law, which will be the same regardless of the state of the gas. In this way,

P₁V₁ = P₂V₂

Where P₁ and V₁ is the pressure and volume of the gas to a state 1 and P₂ and V₂ is the pressure and volume of the same gas in a state 2.

In this case, in the state 1 the gas occupies a volume V₁ = 100 mL at a pressure of P₁ = 150 kPa. Then, in the state 2 the gas occupies a volume V₂ (that we must calculate through the boyle's law) at a pressure of P₂ = 200 kPa.  Substituting these values in the previous equation and clearing V₂, we have,

P₁V₁ = P₂V₂ → V₂ = \frac{P1V1}{P2}  

→ V₂ = \frac{100 mL x 150 kPa}{200 kPa}

→ V₂ = 75 mL

Then, the volume occupied by the gas at 200 kPa is V₂ = 75 mL

6 0
3 years ago
If 3.1 moles of potassium chloride react with oxygen, how many moles of potassium chlorate would be produced?
Likurg_2 [28]

Answer: 19 dollar fortnite card Explanation:who wants it

7 0
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