1/6 yards. All you have to do is add the two upper numbers (numerator) ans then subtract 6/6 - 5/6
La ecuación que nos dice cuantas niñas hay en el colegio es:
A = x - c*m
¿Como encontrar una expresión para la cantidad de niñas?
Sabemos que hay un total de x estudiantes, definimos las variables:
- A = cantidad total de niñas
- B = cantidad total de niños.
Entonces tenemos A + B = x
Tambien sabemos que los estudiantes estan divididos en c cursos, de tal forma que hay m niños por curso.
Entonces c por m es igual a la cantidad total de niños:
c*m = B
Reemplazando esto en la ecuación de arriba podemos obtener:
A + c*m = x
A = x - c*m
Esta es la ecuación que nos da el numero total de niñas en el colegio.
Sí quieres aprender más sobre ecuaciones, puedes leer:
brainly.com/question/18168483
Yes your answers are correct
Answer:
1st picture: (0,4)
The lines intersect at point (0,4).
2nd picture: Graph D
2x ≥ y - 1
2x - 5y ≤ 10
Set these inequalities up in standard form.
y ≤ 2x + 1
-5y ≤ 10 - 2x → y ≥ -2 + 2/5x → y ≥ 2/5x - 2
When you divide by a negative number, you switch the inequality sign.
Now you have:
y ≤ 2x + 1
y ≥ 2/5x - 2
Looking at the graphs, you first want to find the lines that intersect the y-axis at (0, 1) and (0, -2).
In this case, it is all of them.
Next, you would look at the shaded regions.
The first inequality says the values are less than or equal to. So you look for a shaded region below a line. The second inequality says the values are greater than or equal to. So you look for a shaded region above a line.
That would mean Graph B or D.
Then you look at the specific lines. You can see that the lower line is y ≥ 2/5x - 2. You need a shaded region above this line. You can see the above line is y ≤ 2x + 1. You need a shaded region below this line. That is Graph D.
Answer:
middle graph
Step-by-step explanation:
Soluton
The second (middle ) graph is the only one that works.
- First of all when you simplicity the right, you get y = x^2 - 1). That means that x does not go through 0,0. If you put x = 0 into x^ - 1 = 0, you get - 1. So on that basis alone both the first and third graphs are incorrect.
- Second, both xs in the factors are plus, so x^2 is plus, which means the graph opens upward.
