Whats one way to solve fraction additional problems

Mathematics

2 answers:

liubo4ka [24]2 years ago

8 0

The denominator always had to be the same

meriva2 years ago

6 0

The denominator always has to be the same
Example: 1/3 plus 2/4
we know that the LCM (least common multiple) is 12 so you do 1 times 4 and 3 times for because what you do to the bottom, you have to do to the top and for 2/4 we multiply 2 times 3 and 4 times 3 that will leave us with 4/12 plus 6/12 and then you get 10/12 then you reduce that to 5/6. I hope this helps if it doesn't go to Khan Academy its a website and its on Youtube. Good Luck!

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Sum of all natural numbers from100to300 which are divisible by 4and 5 is

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If $x$ is a number that is both divisible by 4 and 5, then

$\begin{cases}x\equiv0\pmod4\\x\equiv0\pmod5\end{cases}$

4 and 5 are coprime, so we can use the Chinese remainder theorem to solve this system and find that $x=20n$ is a solution to the system, where $n$ is any integer. Simply put, any multiple of 20 fits the bill.

Now, there are 11 numbers between 100 and 300 that are divisible by 20 (100, 120, 140, and so on). We have $20n=100$ when $n=5$ , so the sum we want to compute is