24/200×100/100 = 12/100 = 12%
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
Answer:
y=-4+-1
Step-by-step explanation:
hope this is what your looking for
Answer: The answer is (b) [(p∧q)⇒r] ∧ [r⇒(p∧q)].
Step-by-step explanation: Given that The statements 'p', 'q' and 'r' are defined as follows.
p : it is cold,
q : it is humid,
r : it is snowing.
The statement 'it is cold and humid if and only if it is snowing' can be written as
(p∧q) ⇔ r.
We know that r ⇔ s can be written as (r⇒s)∧(s⇒r).
So, (p∧q) ⇔ r can be written as [(p∧q)⇒r] ∧ [r⇒(p∧q)].
Thus, the answer is (b) [(p∧q)⇒r] ∧ [r⇒(p∧q)].
Answer:
2, 4
Step-by-step explanation:
X, Y
5, 2
X is like the floor, Y is like the wall
X: Positive is Right, Negative is left, So you Subtract if you're going left and Add if going right. Aka: 5-3
Y : Positive is Up, Negative is Down. So you Add since you're moving up. Aka: 2+2.
