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lana [24]
3 years ago
6

PLEASE SEE PHOTO!!!!!!!!!!1

Mathematics
1 answer:
hoa [83]3 years ago
5 0

Answer:

Option D

Step-by-step explanation:

You might be interested in
If f(x) = –5x – 4 and g(x) = –3x – 2, find (f – g)(x).
Murljashka [212]
Hello!

We'll start by simplifying the required formula. (f – g)(x) can be rewritten as the following:

f(x) – g(x)

Now insert any known values into the simplified formula above:

(-5x – 4) – (-3x – 2)

Eliminate the parentheses by simplifying:

-5x – 4 + 3x + 2

Combine like terms:

-2x – 2

We have now proven that (f – g)(x) is equal to (-2x – 2).

The correct answer is C.

I hope this helps!
7 0
3 years ago
Read 2 more answers
Solve
victus00 [196]

Answer:

x=14 , y = 21

Step-by-step explanation:

y=x-7...............1

5x+2y=7......2

reset eqn .....2

2y=-5x+7

so; y=-x-7 ×5

2y=-5x+7 ×1

5y = -5x -35

2y = -5x +7

5y-2y = -5 + 5 -35-7

<u>3y</u> = - <u>42</u>

3 3

y = 14

sub y=14 into eqn ...........1

y = -x -7

14 = - x -7

14 +7 = - x

-21 = x

x = 14 , y =-21

3 0
2 years ago
Can someone pls help me with these!!!!
aliya0001 [1]

Answer:

I hope this helps, sorry for my hand writing

8 0
3 years ago
Find the slope of (3,-1) and (1,5) <br> also find the slope of (-4, -5) and (-2, -5)
nikklg [1K]

Answer:

1.-3

2.0

Step-by-step explanation:

5-(-1)/1-3

6/-2

-3

-5-(-5)/-2-(-4)

0/-2+4

0/2

0

3 0
3 years ago
Read 2 more answers
A package of 10 batteries is checked to determine if there are any dead batteries. Four batteries are checked. If one or more ar
frutty [35]

Answer:

There is a probability of 76% of not selling the package if there are actually three dead batteries in the package.

Step-by-step explanation:

With a 10-units package of batteries with 3 dead batteries, the sampling can be modeled as a binomial random variable with:

  • n=4 (the amount of batteries picked for the sample).
  • p=3/10=0.3 (the proportion of dead batteries).
  • k≥1 (the amount of dead batteries in the sample needed to not sell the package).

The probability of having k dead batteries in the sample is:

P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}

Then, the probability of having one or more dead batteries in the sample (k≥1) is:

P(x\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{4}{0} p^{0}q^{4}=1*1*0.7^4=0.2401\\\\\\P(x\geq1)=1-0.2401=0.7599\approx0.76

8 0
3 years ago
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