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11Alexandr11 [23.1K]
3 years ago
11

How can you modify the charges on two particles to quadruple the force between them without moving them? g

Physics
1 answer:
Kruka [31]3 years ago
4 0

Answer:

the charge of each particular must be doubled

Explanation:

We can solve this exercise using Coulomb's law

          F₀ = k q₁ q₂ / r²

tells us that the force is quadrupled and asks if the load

let's call the initial force F₀, let's find the force of the algae they double

                   q₁ = q₂ = 2q₀

we substitute

          F = k 2q₀o 2q₀ / r₁2

          F = 4 F₀

         we see that for the force to multiply by 4, the charge of each particular must be doubled

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Light rays will be diverged by a convex mirror.
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5. The value of a car decreases by 15% each
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the car is worth $2,400

Explanation:

6000*15%=900

900*4=3600

6000-3600=2400

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Which form of energy is due to an object's motion?
Natali [406]

Answer: kinetic energy

Explanation: Kinetic energy has motion which is a moving object

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The chart show the masses and velocities of two colliding objects that stick together after a collision.
finlep [7]

Answer:

<u><em></em></u>

  • <u><em>1,500 kg.m/s</em></u>

Explanation:

First, arrange the information in a table:

Object        Mass (kg)           Velocity (m/s)

  A                    200                      15

  B                     150                    - 10

After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.

According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.

<u>Momentum before the collision, P₁</u>:

          P_1=m_{A,1}\times v_{A,1}+m_{B,1}\times v_{B,1}

         P_1=200kg\times 15m/s+150kg\times (-10m/s)\\\\  P_1=3000kg.m/s-1500kg.m/s=1500kg.m/s

<u>Momentum after the collision</u>:

  • As stated, it es equal to the momentum before the collision: 1,500 kg . m/s
6 0
4 years ago
Need help asap pls
ozzi
Detailed Explanation:

1) Rusting of Iron

4Fe + 3O2 + 2H2O -> 2Fe2O32H2O

Reactants :-
Fe = 4
O = 3 * 2 + 2 = 8
H = 2 * 2 = 4

Products :-
Fe = 2 * 2 = 4
O = 2 * 3 + 2 = 8
H = 2 * 2 = 4

2) Fermentation of sucrose…

C12H22O11 + H2O -> 4C2H5OH + 4CO2

Reactants :-
C = 12
H = 22 + 2 = 24
O = 11 + 1 = 12

Products :-
C = 4 * 2 + 4 = 12
H = 4 * 5 + 4 = 24
O = 4 * 2 + 4 = 12

Looking closely at the way I have taken the total number of elements on the reactants and products side, you can solve the rest.

All the Best!
8 0
3 years ago
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