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3 years ago

An example of a neologism from the Internet is:

Physics

1 answer:

notsponge [240]3 years ago

7 0

Answer:

b.peeps(meaning "people "or "the friends your hang out with")

You might be interested in

A 755 N diver drops from a board 10.0 m above the water's surface. Find

MrRa [10]

Answer:

F = 755 N and h = 10.0 m and a = 9.8 m/s 2 and m=? and v = ?

5 0

3 years ago

Which statements describe acceleration? Check all that apply.

DiKsa [7]

Answer:

Negative acceleration occurs when an object speeds up in the negative direction.

Positive acceleration occurs when an object speeds up in the positive direction.

Explanation:

This might be wrong but I get some points for a answer..

8 0

3 years ago

The momentum of an ostrich is calculated to be 5,400 kg*km / hr Its mass is known to be 120 kg. Was the ostrich moving or standi

Dmitry [639]

The correct answer to the question is : The ostrich is motion.

EXPLANATION:

As per the question, the momentum of ostrich P = 5400 Kg. Km/hr.

The mass of the ostrich m = 120 Kg.

The momentum of a body is defined as the product of mass with velocity.

Mathematically P = mv.

The velocity of the ostrich v is calculated as -

v = $\frac{P}{m}$

= $\frac{5400}{120}\ Km/hr$

= 45 Km/hr

Hence, the ostrich is in motion as it is moving with a velocity of 45 Km/hr.

7 0

3 years ago

Read 2 more answers

A baseball approaches home plate at a speed of 44.0 m/s, moving horizontally just before being hit by a bat. The batter hits a p

Luda [366]

Explanation:

It is given that,

Speed of the baseball, u = 44 m/s

Speed of the baseball, v = 53 m/s

Mass of the ball, m = 145 g = 0.145 kg

Time of contact between the ball and the bat, t = 2.2 ms = 0.0022 s

$F=ma$

$F=\dfrac{mv}{t}$

$F_1=\dfrac{0.145\ kg\times 44\ m/s}{0.0022\ s}$

F₁ = 2900 N...........(1)

$F=ma$

$F=\dfrac{mv}{t}$

$F_2=\dfrac{0.145\ kg\times 53\ m/s}{0.0022\ s}$

F₂ = 3493.18 N.........(2)

In average vector form force is given by :

$F=F_1+F_2$

$F=(2900i+(-3493.18)\ N$

$F=(2900i-3493.18j)\ N$

Hence, this is the required solution.

6 0

4 years ago

A wave of amplitude 20mm has intensity Ix. Another wave of the same frequency but of amplitude 5mm has an intensity Iy.

Alexeev081 [22]

Answer:

(C) 16

Explanation:

Given:

The amplitude of first wave (s₁) = 20 mm

The amplitude of second wave (s₂) = 5 mm

Intensity of first wave = Iₓ

Intensity of second wave = $I_y$

The intensity associated with a wave depends on the amplitude of the wave.

The intensity (I) is directly proportional to the square of the amplitude (s) of the wave and is expressed as:

$I=ks^2\\Where\ k\to constant\ of\ proportionality$

Now, the intensities of the two waves are given as:

$I_x=ks_1^2=k(20)^2\\\\I_y=ks_2^2=k(5)^2$

Dividing both the intensities, we get:

$\frac{I_x}{I_y}=\frac{k(20)^2}{k(5)^2}\\\\\frac{I_x}{I_y}=\frac{400}{25}\\\\\frac{I_x}{I_y}=16$

Therefore, the option (C) is correct.

5 0

3 years ago