Answer:
S = V0 t + 1/2 a t^2
S = 5 m/s * 300 s + 1/2 * 1.2 m/s * (300 s^2)
S = 1500 m + .6 * 90000 m = 55,500 m
Check: V0 = 5 m/s
V2 = V0 + a t = 5 + 1.2 * 300 = 365 m/s
Vav = (V1 + V2) / 2 = (5 + 365) / 2 = 185 m/s (note uniform motion)
S = 185 * 300 = 55,500 m
We calculated V2 above at 365 m/s the speed after 300 sec
Need to draw it first.....
but there is no option here to draw .. why?
anyway , here the car is going with a uniform velocity..
so the acceleration of the car=0, a=0
so resistive force on the car=component along the inclined plane of the weight of the car=mg*cos(90-15)=960*9.8*cos 75=?
The value of the angle of the incline

at which the block starts to slide is the angle at which the component of the weight parallel to the incline becomes equal to the frictional force that keeps the block on the incline:

where the term on the left is the component of the weight parallel to the incline, and the term on the right is the frictional force, which is the product between the coefficient of friction

and the normal reaction of the incline N.
The normal reaction of the incline, N, is equal to the component of the weight perpendicular to the incline:

Therefore, the initial equation becomes

From which we find


For angles above this value, the block will start sliding down, otherwise the block will stay on the incline.
Answer:
The magnitude of change in momentum of the ball is
and impulse is also
Explanation:
Given:
Velocity of a pitched ball

Velocity of ball after impact

From the formula of change in momentum,

Here mass is not given in question,
Mass of ball is 
Change in momentum is given by,


Magnitude of change in momentum is

And impulse is given by


So impulse and
Therefore, the magnitude of change in momentum of the ball is
and impulse is also