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3 years ago

150^ how do i simplify this

Mathematics

2 answers:

melomori [17]3 years ago

7 0

<span>Simplified Square Root for √150 is 5√6 (i think)

</span>

Anna007 [38]3 years ago

7 0

BRACKET THE ANSWER THEN SIMPLIFY

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What is the solution to the equation below? (Round your answer to two

Sphinxa [80]

Answer:

The answer would be C

Step-by-step explanation:

Multiply 6 by 0.87 to get 5.22, and then multiply 5.22 with 3 to get your answer :)

8 0

3 years ago

Find the domain and range of the graph

ozzi

9514 1404 393

Answer:

domain: [-6, -1)
range: [-5, 4]

Step-by-step explanation:

You have correctly determined the domain to be from x = -6 to x < -1. In interval notation, that would be ...

[-6, -1)

The range is the vertical extent of the graph. It extends from a minimum of y = -5 to a maximum of y = +4 at the top of the curve. In interval notation, that would be ...

[-5, 4]

8 0

3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

3 years ago

Read 2 more answers

I really need help with this question

yan [13]

Answer:

where is it at

Step-by-step explanation:

sheeeeeeesh

3 0

3 years ago

During one month, a rental agency rented a total of 155 cars, trucks, and vans. Nine times as many cars were rented as vans, and

solong [7]

Answer:

The system of three equations is equal to

$x+y+z=155$

$y=9x$

$z=3y$

Step-by-step explanation:

Let

x ----> the number of cars rented during one month

y ----> the number of vans rented during one month

z ----> the number of trucks rented during one month

we know that

$x+y+z=155$ ----> equation A

$y=9x$ ---> equation B

$z=3y$ ----> equation C

8 0

3 years ago