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Debora [2.8K]
3 years ago
9

How do I round 3.047 to the nearest hundred and show the math

Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0

I believe you meant "hundredth" and not "hundreds"


<u><em>Answer:</em></u>

3.05


<u><em>Explanation:</em></u>

<u>To round a number to the nearest hundredth, we need to check the digit in the thousandth position:</u>

1- If this digit was less than 5, we round down. This means that the number i the hundredth position is left as it is and all digits after it are converted to zeroes

2- If this digit was equal to or greater than 5, we round up. This means that we add one to the digit in the hundredth position and then convert all digits after it to zeroes


<u>The given number is:</u>

3.047


The digit in the thousandth position is 7 which is greater than 5.

Therefore, we round up


<u>This means that our number would be:</u>

3.050


The last zero is meaningless and can be discarded leaving us with 3.05 as an answer


Hope this helps :)

dexar [7]3 years ago
5 0
I'm guessing you mean 'hundredths', not 'hundreds', else that'll be 0.

First, find the hundredths spot.
The hundredths number is 4.

Look at the next number. 
If it is more than 4, round it up.
If it is less than 5, round it down.

7 is more than 4, so we round up. 

The final answer is 3.05.

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Answer:

1947.78 inches or 162.31 feet.

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

From 1 to ___, ____, and 2 is half and half that would be 2 and a half. the only solution would be 1/3

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2 years ago
The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

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saveliy_v [14]

Answer:

Option D -  8 children

Step-by-step explanation:

Twenty four divided by eight the equation is irelated to which MCQ

24/3 = 8

Option D, A cookie jar contains 24 cookies. Each child receives 3 cookies.

The right answer is 24 cookies that are in a jar eaten by children,

If each child get 3 cookies,  

Hence, 24/3 the answer will be = 8

Means 8 children are there to eat 3 cookies that is 24.

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