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3 years ago

10

Suppose that the perimeter a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width ractangle, in f

eet.

1 answer:

Vesnalui [34]3 years ago

8 0

Answer:7feet

Step-by-step explanation:

perimeter(p)=54ft

Width(w) +13=Length(L)

Perimeter=2xLength+2xwidth

P=2xL+2xw

L=w+13

54=2(w+13)+2w

54=2w+26+2w

Collect like terms

54-26=2w+2w

28=4w

Divide both sides by 4

28/4=4w/4

7=w

Width =7feet

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A circle has a circumference of 12. It has an arc of length 11.

riadik2000 [5.3K]

Answer:

The central angle is 330 degrees

Step-by-step explanation:

The arc length is equal to the circumference time the fractional part of the circle

arc length = circumference * x/360

11 = 12 * x/360

Divide each side by 12

11/12 = 12/12 *x/360

11/12 = x/360

Multiply by 360

11*360/12 = x /360 *360

330 = x

The central angle is 330 degrees

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3 years ago

Can someone hep me on this

Pavel [41]

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3 years ago

Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou

Anna35 [415]

For this case we have the following equation:
$3 \sqrt{x+6}=-12$
Rewriting we have:
$\sqrt{x+6}= \frac{-12}{3}$
$\sqrt{x+6}=-4$
We raise both members of the equation to the square:
$(\sqrt{x+6})^2=(-4)^2$
Rewriting we have:
$x+6=16$
$x=16-6$
$x=10$
It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
$3 \sqrt{10+6}=-12$
$3 \sqrt{16}=-12$
$3(4)=-12$
$12=-12$
Answer:
The solution is:
$x=10$
It's a extraneous solution

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3 years ago

Curtis threw 15 darts at a dartboard.40% of his darts hit the bull’s eye.how many darts not hit the bulls eye?

Harlamova29_29 [7]

Answer:

9

Step-by-step explanation:

The number of darts that failed to hit the bulls eye is 40% of 15 subtracted from 15

Since 40% of the darts hit the bulls eye .

Therefore

40% of 15

40/100 x 15

0.4 x 15

6

This means that 6 darts hit the bulls eye.

Therefore,number of darts that did not hit the bulls eye is

15 - 6 = 9

9 darts failed to hit the bulls eye

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2 years ago

How are the shapes alike

Andrews [41]

Answer:

Each circle (A, B, and C) contain shapes that all share at least one characteristic. Some shapes are contained in more than one circle because they share more than one characteristic. For example, shape 3 fits the rule for circles A and B, but not circle C. It lies within circles A and B, but not circle C.

Step-by-step explanation:

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2 years ago