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4 years ago

10

Suppose that the perimeter a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width ractangle, in f

eet.

1 answer:

Vesnalui [34]4 years ago

8 0

Answer:7feet

Step-by-step explanation:

perimeter(p)=54ft

Width(w) +13=Length(L)

Perimeter=2xLength+2xwidth

P=2xL+2xw

L=w+13

54=2(w+13)+2w

54=2w+26+2w

Collect like terms

54-26=2w+2w

28=4w

Divide both sides by 4

28/4=4w/4

7=w

Width =7feet

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when the smallerof two consecutive integers is added to two times the larger,the result is 17.find the integers

Gnesinka [82]

Formula:

x + 2(x+1) = 17
x + 2x + 2 = 17
3x + 2 = 17
3x = 15
x = 5

So, the answer is 5 and 6

Hope this helped!

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3 years ago

List all the factors of the composite number 146

Temka [501]

1 and 146
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3 years ago

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4 years ago

The sum of two numbers is 6. Two less than three times the smaller is equal to the larger

Natasha_Volkova [10]

So... let's say, we have two numbers "a" and "b",
"a" is the smaller one, "b" is the larger one
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a + b = 6

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3a - 2

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3 years ago

Read 2 more answers

Solve x2 + 8x – 3 = 0 using the completing-the-square method.

aivan3 [116]

$x = -4 \pm \sqrt{19}$

Step-by-step explanation:

Let us put 3 on the right side and rewrite the equation as

$x^2 + 8x = 3$

By putting 16 on both sides, our equation becomes

$x^2 + 8x + 16 = 3 + 16 = 19$

$\Rightarrow (x + 4)^2 = 19$

Taking the square root of the equation, we get

$x + 4 = \pm \sqrt{19}$

Finally, solving for x,

$x = -4 \pm \sqrt{19}$

3 0

2 years ago