All categories

3 years ago

Determine the vertex of the quadratic function represented by f(x)=(x+3)2−4f(x)=(x+3)

Mathematics

1 answer:

igomit [66]3 years ago

6 0

Answer:idk but good luck. Hope you find your answer

Step-by-step explanation:

You might be interested in

Help me, please! I need to start my new semester today so please helpppp!!!!!

Vadim26 [7]

Answer:

3/6

Step-by-step explanation:

I think it is asking for an answer choice equal to 1/2, and 3/6 is equal to 1/2.

Do you have a picture of the actual question?

6 0

2 years ago

Complete the equation for the standard form of the line that has an x-intercept of 3 and a y-intercept of 5.

Ugo [173]

Answer:

5x+3y=15

Step-by-step explanation:

We are given two coordinates (3,0) (0,5)

Start by finding slope

y2-y1/x2-x1= 5-0/0-3= -5/3 this is your slope m.

y=mx+c

y= -5/3x+c (but remember standard line is ax+by=c) so we have to switch sides

5/3x + y=5 (remember standard form has no fraction so multiply by 3 on all sides)

5x+3y=15

3 0

3 years ago

Read 2 more answers

Which ratio is equivalent to 7:3?

aliina [53]

Answer:

The answer is B.

Step-by-step explanation:

7x4 is 28 which means you have to multiply 3x4. That gives you 12. 28:12 is the proper ratio. (Hope this helped!)

3 0

3 years ago

Read 2 more answers

Help asp I’m on timed test

g100num [7]

Answer:

Step-by-step explanation:

6 0

2 years ago

A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar

Arisa [49]

Answer:

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

$n=17$ represent the sample selected

$\alpha=0.1$ represent the significance

$s^2 =4.7^2 =22.09$ represent the sample variance

$\sigma^2_0 =3.5^2 =12.15$ represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 12.15$

Alternative hypothesis: $\sigma^2 \neq 12.15$

The statistic for this case is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

The degrees of freedom are:

$df =n-1= 17-1=16$

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0

3 years ago