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ipn [44]
3 years ago
6

Machine A produces 75 fishing lures per minute. Machine B produces 50 of the same lure per minute. How long will it take both ma

chines running to produce 2100 fishing lures? A.14.4 minutes B.16.8 minutes C.18.2 minutes D.20.7 minutes
Mathematics
1 answer:
Daniel [21]3 years ago
3 0

Answer: Option B

16.8 minutes

Step-by-step explanation:

Machine A produces 75 fishing lures per minute.

Machine B produces 50 fishing lures per minute.

Let's call t time in minutes.

So we want to know how long it will take to produce 2100 fishing lures

We propose the following equation

75t + 50t = 2100

Now we solve for t

125t = 2100

t = 16.8\ min

The answer is Option B

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The product of (√3x + √5)(√15x+2√30) assuming x ≥ 0 is 3√5x² + 6√10x + 5√3x + 10√6

<h3>What is the product of the expression?</h3>

It follows from the task content that the expression given whose product is to be evaluated is;

(√3x + √5)(√15x+2√30)

Hence, by multiplying the terms with each other accordingly; we have;

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= 3√5x² + 2√90x + √75x + 2√150

= 3√5x² + 2×3√10x + √75x + 2√150

= 3√5x² + 2×3√10x + 5√3x + 2√150

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= 3√5x² + 6√10x + 5√3x + 10√6

Ultimately, the product of the expression is; 3√5x² + 6√10x + 5√3x + 10√6

Learn more about product:

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