Answer: 0.665.
Step-by-step explanation:
60% of the bags are from supplier A, and 95% of them are undamaged.
40% of the bags are from supplier B, and 75% of them are undamaged.
Then, the number of undamaged bags from supplier A is:
0.6*0.95 = 0.57 or 57%
from B is:
0.4*0.75 = 0.3 or 30%
This means that the percentage of undamaged bags is:
57% + 30% = 87%.
Then, the probability that an undamaged bag is from supplier A is equal to the percentage of undamaged bags that came from supplier A (57%) and the total percentage of undamaged bags (87%) this is:
P = 57%/87% = 0.655 or 65.5%
Then the probability that an undamaged bag comes from supplier A is 0.665.
It would have to be Midsegment!!!!!
Answer:
7.
I) must be true
II) 1 - 1 < 2 - 4 --> false
III) (-10)*(-10) < 1*1 --> false
IV) 1/2 < 2/10 --> false
So (B) 1 must be true
8.
x!·(x + 1)!/2 = (x + 1)!^2 / (2·(x + 1)) = (17 + 1)!^2 / (2·(17 + 1)) = 18!^2 / 6^2
(D)
9.
2·√3·6 = √((2·√3)^2 + 6^2)·h --> h = 3 --> (C)
Http://www0.dlshs.org/webpages/hirschs/documents/Chapter6Solutions.PDF this website might have the answer your looking for
