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zmey [24]
3 years ago
9

Researchers surveyed recent graduates of two different universities about their income. The following two-way table displays dat

a for the sample of graduates who responded to the survey. Of graduates in the sample, what fraction came from university A?
https://gyazo.com/024c033fb3022b87aee5e6ca3695277b
Mathematics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer:

22% is the answer

Step-by-step explanation:

First, divide 35(the number of students who have a income under 30,000 in  university A) by 160(the number of students in university A)

Secondly once you got the answer which is 0.21875. You round it up to 22% which is that answer.

HOPE THIS HELPS! :)

mario62 [17]3 years ago
3 0

Answer:

8/15

Step-by-step explanation:

First lets find the fraction. (160 people came from University A and there were 300 people in total, therefore the fraction would be:

160/300

Next, lets simplify this.

8/15

Hope this helps!

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Write and expression to find the perimeter of a rectangle with a length of 8 mm and width of x mm
Mrrafil [7]

Answer:

P=16+2x

Step-by-step explanation:

The formula for finding the perimeter of a rectangle is P=2l+2w.

Plug the length of 8 and the width of x into the formula.

You'll get P=2(8)+2(x).

Multiply. 2•8=16 and 2•x=2x.

Your expression is P=16+2x.

I hope this helps.

3 0
3 years ago
Is 5(2x-3y) and 10x-3y equivalent?
stiks02 [169]

Answer:

No

Step-by-step explanation:

Apply the distributive property to 5(2x - 3y):

Multiply 5 by each term inside the parentheses.

5(2x - 3y) = 10x - 15y

The other expression is 10x - 10y.

The terms 10x in both expressions are equal.

Since the term -15y is not equal to the term -10y, the expressions are not equivalent.

3 0
3 years ago
What is the value of x? Justify each step using proof reasoning. AB + BC = AC a.segment addition postulate 2x + 6x + 8 = 32 b. s
Annette [7]
2x+6x+8=32
8x+8=32
    -8 =-8
8x=24
 8/8=x  24/8 =4
x=4
7 0
4 years ago
Help solve for “q”<br> —————————————
VMariaS [17]

Digram:-

\\

\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){$\underline{\boxed{\large\sf a + b = 180^{\circ}}$}}\put(4.5,1.3){$\sf a^{\circ}$}\put(5.7,1.3){$\sf b^{\circ}$}\end{picture}

\\

STEP :-

\dashrightarrow \tt(4q - 1) {}^{ \circ}  +  {117}^{ \circ}  = 18 {0}^{ \circ}

{Linear pair}

\\  \\

\dashrightarrow \tt(4q - 1) {}^{ \circ}= 18 {0}^{ \circ}   - {117}^{ \circ}

\\

\dashrightarrow \tt(4q - 1) {}^{ \circ}=63^{ \circ}

\\

\dashrightarrow \tt4q - 1{}^{ \circ}=63^{ \circ}

\\

\dashrightarrow \tt4q =63^{ \circ} + 1{}^{ \circ}

\\

\dashrightarrow \tt4q =64{}^{ \circ}

\\

\dashrightarrow \tt \: q =  \dfrac{64}{4}^{ \circ}

\\

\dashrightarrow \tt \: q =  \dfrac{16 \times 4}{4}^{ \circ}

\\

\dashrightarrow \tt \: q =  \dfrac{16 \times \cancel4}{\cancel4}^{ \circ}

\\

\dashrightarrow \tt \: q =  \dfrac{16}{1}

\\

\dashrightarrow \bf q = 16 \degree

\\  \\

Verification:

\\

\dashrightarrow \tt(4 \times 16- 1) {}^{ \circ}  +  {117}^{ \circ}  = 18 {0}^{ \circ}

\\

\dashrightarrow \tt(64- 1) {}^{ \circ}  +  {117}^{ \circ}  = 18 {0}^{ \circ}

\\

\dashrightarrow \tt63^{ \circ}  +  {117}^{ \circ}  = 18 {0}^{ \circ}

\\

\dashrightarrow \tt180^{ \circ}  = 18 {0}^{ \circ}

\\

LHS = RHS

HENCE VERIFIED!

8 0
2 years ago
PLEASE HURRY MY MOM IS WAIRING ON ME What function equation is represented by the graph
mafiozo [28]
I think it's c sry if wrong
6 0
3 years ago
Read 2 more answers
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