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IceJOKER [234]
3 years ago
14

What transformation was not done to the linear parent function, f(x) = x, to get the function

g%28x%29%20%3D%20-%5Cfrac%7B1%7D%7B2%7D%28x-3%29%2B7" id="TexFormula1" title="g(x) = -\frac{1}{2}(x-3)+7" alt="g(x) = -\frac{1}{2}(x-3)+7" align="absmiddle" class="latex-formula">?
A. Shifted left 3 units
B. Vertically compressed by a factor of 2
C. Reflected over the x-axis
D. Shifted up 7 units
Mathematics
1 answer:
Andru [333]3 years ago
5 0

Answer:

The transformation was not done is Shifted left 3 units

Step-by-step explanation:

* Lets talk about the transformation

- If the function f(x) reflected across the x-axis, then the new

 function g(x) = - f(x)

- If the function f(x) reflected across the y-axis, then the new

 function g(x) = f(-x)

- If the function f(x) translated horizontally to the right  

 by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  

 by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

 by k units, then the new function g(x) = f(x) – k

- A vertical stretching is the stretching of the graph away from

 the x-axis

- A vertical compression is the squeezing of the graph toward

 the x-axis.

- if k > 1, the graph of y = k•f(x) is the graph of f(x) vertically

  stretched by multiplying each of its y-coordinates by k.

- if 0 < k < 1 (a fraction), the graph is f(x) vertically compressed

 by multiplying each of its y-coordinates by k.

- if k should be negative, the vertical stretch or compress is

 followed by a reflection across the x-axis.  

* now lets solve the problem

∵ f(x) = x

∵ g(x) = -1/2 (x - 3) + 7

# -1/2 means the graph is vertically compressed by a factor of 2

  and reflected over the x-axis

# x - 3 means the graph shifted to the right 3 units

# + 7 means the graph shifted up 7 units

* The transformation was not done is Shifted left 3 units

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0 divided by 2 is 0.

You can use the multiplicative identity property: the product of any number and zero is still zero.

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Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

   the bracket to keep the equation as it

∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

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