Answer:
What grade is this question?
Step-by-step explanation:
in a momment im in class
<em>Acceleration (a) = 5.1 m/s</em>²
<em>Initial speed (u) = 16 km/h </em>⇒

<em>m/s </em>≈ <em>4.5m/s</em>
<em>
</em><em>Final speed (v) =118 km/h </em>⇒

<em>m/s</em> ≈ <em>32.8m/s</em>
<em>
</em>Distance(S) travel in that particular instant is carried out by 'Third equation of motion' i.e., v² = u² + 2aS
<em>So, When all quantities are in S.I. unit then,
</em>putting the values in the equation of motion,
<em /><em>As we have to carry out the distance covered,
</em><em>2</em>·<em>a</em>·<em>S = v</em>² <em>- u</em>²
<em>S = </em>

Putting values in derived equation,
⇒ <em>S = </em>

⇒ <em>S = </em>

⇒ <em>S = </em>

⇒ <em>S </em>≈ <em>103.489</em> <em>m
</em>
<em>
The total distance covered in that given condition is approx. 103.289 m.</em>
Answer:
1.x^2-5x
2.2x^2+15x+18
3. x^2+20x+18
Step-by-step explanation:
1. x(x-5) x*x-5*x = x^2-5x
2. (x+6)(2x+3) x*2x+x*3+6*2x+6*3= 2x^2+15x+18
3.(2x^2+15x+18)-(x^2-5x)=x^2+20x+18
Answer:
7 yards
Step-by-step explanation:
C
Opposite / hypotenuse
Sin 45 degrees= 7/x