Since there aren't grams and just moles, the theoretical yield is one whole mole. If the molar mass is <span>142.04 g/mol, that is your answer. Hope I helped!</span>
The correct answer is by working in tandem in a symbiotic manner.
Agouti, a tiny rodent, and the Brazil nut tree are interdependent in the Amazon rainforest. The Brazil nut tree drops its ripe pods to the ground, but if it weren't for the agouti's razor-sharp teeth, the pods wouldn't be broken open. The only animal in the forest that has the propensity to separate pods is the agouti. The agouti benefits from eating the Brazil nuts; in exchange, the agoutis bury and conceal the extra nuts; many of these nuts assume the shape of roots and replenish the Brazil nut trees' supplies. Brazil nut trees appear to only bear fruit in undisturbed forests and are vulnerable to deforestation. They rely on other plants in the rainforest, agoutis for seed dissemination, bees for pollination, and other animals to survive. The Brazil nut tree will also vanish if these other species do.
Learn more about Agouti here:-
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Answer:
it will affect the mass by changing in pressure will affect the volume (and therefore density) of gases, but will not noticeably affect the volume (or density) of solids and liquids. For gases: An increase in pressure leads to a decrease in volume and an increase in density. A decrease in pressure leads to an increase in volume and an decrease in density.
Explanation:
Answer:
204g of NH3
Explanation:
The balanced equation for the reaction is given below:
N2 + 3H2 —> 2NH3
Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:
From the balanced equation above,
1 mole of N2 reacted to produce 2 moles of NH3.
Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.
Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:
Number of mole of NH3 = 12 moles.
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Mass of NH3 =..?
Mass = mole x molar mass
Mass of NH3 = 12 x 17
Mass of NH3 = 204g.
Therefore, 204g of NH3 will be produced from the reaction.
Refer to this page (http://www.mrbigler.com/misc/energy-of-formation.PDF) for the data of heat of formation. For elemental forms, ΔHf is 0. Then, we use Hess' law.
ΔHrxn = Σ(n×ΔHf of products) - Σ(n×ΔHf of reactants)
Calculate ΔHrxn for Fe₂O₃:
Fe₂O₃ + 2 Al --> Al₂O₃ + 2 Fe
ΔHrxn = (-1675.7 kJ/mol) - (-824.2 kJ/mol)
ΔHrxn = -851.5 kJ/mol * 141 g * 1 mol Fe₂O₃/159.69 g
ΔHrxn = -751.84 kJ
Next, we solve ΔHrxn for CuO:
3 CuO + 2 Al --> Al₂O₃ + 3 Cu
ΔHrxn = (-1675.7 kJ/mol) - (-157.3 kJ/mol)
ΔHrxn = -1518.4 kJ/mol
Then, we find the mol CuO needed:
-751.84 = n*(-1518.4)
n = 0.495 mol
Since the molar mass of CuO is 79.545 g/mol.
Mass = 0.495 mol*79.545 g/mol = <em>39.4 g CuO</em>