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Crank
3 years ago
6

How will volume affect the mass of a liquid?

Chemistry
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

it will affect the mass by changing in pressure will affect the volume (and therefore density) of gases, but will not noticeably affect the volume (or density) of solids and liquids. For gases: An increase in pressure leads to a decrease in volume and an increase in density. A decrease in pressure leads to an increase in volume and an decrease in density.

Explanation:

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Lead is malleable, so it can be pounded into flat sheets without breaking. How does the bonding within lead help to explain this
damaskus [11]

Answer:

correct answer would be c

8 0
3 years ago
the following data were collected. time, s [A], M 0 1.00 1 0.430 2 0.270 3 0.200 4 0.160 What is the order of the reaction and t
Tems11 [23]

Answer:

I'll give you the graphs that you need to look at:1st order: the graph you need to make is ln[A] vs t. If you get a straight line, the reaction is 1st order and the slope will equal to the rate constant K.2nd order: the graph you need to make is 1/ln[A] vs t. If this graph shows a straight line, the reaction is 2nd order and the slope will equal the rate constant K.

Explanation:

7 0
3 years ago
Write a condensed structural formula for the repeat unit of the Kevlar molecule
shusha [124]

Explanation:

Kevlar is a fiber which is used in making of bullet proof vests and armors. It is a co-polymer which is formed by condensing two organic molecules 1,4-phenylene-diamine and terephthaloyl chloride.

NH_2C_6H_4NH_2+Cl-(CO)-C_6H_4-(CO)-Cl\xrightarrow[-2HCl]{ }

                      NH_2-C_6H_4-NH-CO-C_6H_4-COOH

For Structure refer to image attached.


4 0
3 years ago
Read 2 more answers
A balloon at 25°C has 30 L. What will the balloon's volume at 35°C?
anygoal [31]

The balloon's volume at 35°C : V₂=31.01 L

<h3>Further explanation</h3>

Given

T₁ = 25°C+273 = 298 K

V₁ = 30 L

T₂ = 35 °C + 273 = 308 K

Required

The new volume (V₂)

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Input the value :

V₂=(V₁.T₂)/T₁

V₂=(30 x 308)/298

V₂=31.01 L

8 0
3 years ago
(a) if a sample containing 2.00 ml of nitroglycerin is detonated, how many total moles of gas are produced? (b) if each mole of
gregori [183]
Detonation of nitroglycerin: 

4C_3H_5N_3O_9  ------\ \textgreater \  12CO_2+6N_2+O_2+H_2O

<span>Mass nitroglycerin = 2.00 mL x 1.592 g/mL = 3.184 g 
</span>
Moles = mass / molar mass = 3.184<span> g/ 227.0872 g/mol = 0.01402
</span>
the ratio between nitroglycerin and Carbon dioxide is 4 : 12 
So, moles CO2 = 0.01402 x 12 / 4 =0.0420

the ratio between nitroglycerin and N2 is 4 : 6 
moles N2 = 0.01402 x 6 / 4 =0.0841

<span>the ratio between nitroglycerin and O2 is 4 : 1 </span>
moles O2 = 0.01402 x 1 / 4 = 0.0035

<span>the ratio between nitroglycerin and water is 4 : 1 </span>
<span>in the same way moles water = 0.005258 </span>

total moles = 0.0420 + 0.0841 + 0.0035 + 0.005258 = 0.130758

0.130758<span> x 55 = 5.78 L </span>

Mass N2 = 0.0841 mol x 28.0134 g/mol = 2.3548 g


6 0
3 years ago
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