Are the cells in this image prokaryotic or eukaryotic

Which Of These Periods Contain Elements With Electrons s,p,d and f orbitals? Periods 1-3 Periods 1-4

Elanso [62]

The answer would be periods 6-7 :)

7 0

3 years ago

10. Well into the twentieth century, many scientists believed the ocean floor was A. rocky. B. round. C. flat. D. sandy.

Murljashka [212]

<span>In the 20th century, the scientist believed that the floor of the ocean floor is flat. But later on discovered that their theory is wrong. The ocean floor is not flat and featureless. One technology helped the scientist to study in advance and in details the real feature of the ocean floor. They used sound waves to know the distance of the water from floor level to the top. They also discovered that ranges of mountains lies under the ocean. Sonar was one of the technologies they used to study the sound waves emitted by the ocean. Hope i was helpful :)</span>

8 0

3 years ago

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Please help! I don’t know what 4 and 5 is

alekssr [168]

4. Snow removal, as its snows a lot in Pennsylvania.
5. For number 5 please tell me which services the company offers & keep in mind the weather patterns are pretty hot & sunny in Florida, especially during the summers. If the company provides services (such as snow removal) Florida would hardly need any, causing the company to make less profit.
Good luck & please be sure to try your best. You got this!

6 0

2 years ago

When a solute is dissolved in water, it forms……

il63 [147K]

Answer:

an aqueous species is the answer

3 0

3 years ago

A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final

KATRIN_1 [288]

Answer : The initial temperature of the limestone is $1.05\times 10^{2}^oC$ .

Solution : Given,

Mass of limestone = 62.6 g

Mass of water = 75 g

Final temperature of limestone = $51.9^oC$

Final temperature of water = $51.9^oC$

Initial temperature of water = $23.1^oC$

The specific heat capacity of limestone = $0.921J/g^oC$

The specific heat capacity of water = $4.186J/g^oC$

The formula used :

q = m × c × ΔT

where,

q = heat required

m = mass of an element

c = heat capacity

ΔT = change in temperature

According to this, the energy as heat lost by the system is equal to the gained by the surroundings.

Now the above formula converted and we get

$q_{system}=-q_{surrounding}$

$m_{system}\times c_{system}\times (T_{final}-T_{initial})_{system}= -[m_{surrounding}\times c_{surrounding}\times (T_{final}-T_{initial})_{surrounding}]$

$m_{limestone}\times c_{limestone}\times (T_{final}-T_{initial})_{limestone}= -[m_{water}\times c_{water}\times (T_{final}-T_{initial})_{water}]$

Now put all the given values in this formula, we get

$62.6g\times 0.921J/g^{0}C \times (51.9^{0}C-T_{\text{ initial limestone}})= -[75g\times 4.186J/g^{0}C \times (51.9^{0}C-23.1^oC)]$

By rearranging the terms, we get the value of initial temperature of limestone.

$T_{\text{ initial limestone}}=104.926^{0}C=1.05\times 10^{2}^oC$

Therefore, the initial temperature of the limestone is $1.05\times 10^{2}^oC$ .

8 0

3 years ago

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