Answer:
1600 calories
Explanation:
Data obtained from the question include:
M (mass of water) = 20g
T1 (initial temperature) = 383°C
T2 (final temperature) = 303°C
ΔT (change in temperature) = T1 - T2 = 383 - 303 = 80°C
C (specific heat capacity of water) = 1 calorie/g°C
Q (heat) =?
Using the the equation Q = MCΔT, the heat in calories absorbed by the water can be obtained as follow:
Q = MCΔT
Q = 20 x 1 x 80
Q = 1600 calories
Therefore, the heat absorbed by the water is 1600 calories
Correct answer is five C, eight H, and two O
Answer:
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Explanation:
Answer:
12 moles of CO
Explanation:
According to Avogadro, one mole of a substance, contains the same number of elementary entities as 12g of carbon-12. Now the number of elementary entities (atoms, molecules, ions, particles etc) in any substance is given by the Avogadro's constant.
Now since 1 mole of a substance contains Avogadro's number of atoms, it means that the substance with the highest number of moles will have the highest number of atoms.
With this in mind we can see that 12 moles of CO is expected to contain 72.24 ×10^23 atoms of CO. Hence the answer.
Answer:
Explanation:
Iron(III) oxide gets mixed with elemental carbon and heated to make elemental iron and carbon dioxide.
2Fe₂O₃ + 3C = 4 Fe + 3 CO₂
2 x 160 3 x 12 4 x 56
320 gram of iron ( iii ) oxide requires 36 g of carbon for reduction
1 kg of iron will require 36 / 320 g of carbon
carbon required = 36 / 320 g
= .1125 g
= .113 g rounding off to 3 significant fig .
b )
320 gram of iron ( iii ) oxide produces 224 g of iron after reduction
1 g of iron will produce 224 / 320 g of iron
iron produced = 224 / 320 g
= 0.700 g .