Answer:
P = 0.444 atm
Explanation:
The reaction of decomposition of H₂S is:
H₂S(g) ⇄ H₂(g) + S(g)
<em>Initial</em> 0.245 0 0
<em>Equilibrium </em>0.245-x x x
The equilibrium constant (Kp) of the above reaction is the following:
(1)
Knowing that initally, only H₂S is present at P = 0.245, the Kp of equation (1) at equilibrium is:
Using the quadratic formula we get x₁ = 0.199 and x₂ = -1.058.
Taking only the possitive number we have that:
Therefore, the total pressure in the container at equilibrium is:
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