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bearhunter [10]
3 years ago
12

4. The distance covered by the cook in Triangle A equals _______________ eighteen-inch steps.

Mathematics
1 answer:
laiz [17]3 years ago
3 0
We know that

<span>to convert feet to inches we must multiply by 12

</span>4. The distance covered by the cook in Triangle A equals 
a) fridge and stove-----------> 5*16*12=960 in
b) fridge and sink-------------> 10*22*12=2640 in
c) sink and stove--------------> 15*16*12=2880 in
then add, 960 + 2640 + 2880 = 6480 in

the answer asks for the distance in 18 in lengths 
so divide 6480 by 18 -------------> 6480/18=360 

the answer part N 4) is 360 eighteen-inch steps
<span>
5. The distance covered by the cook in Triangle B equals 
a) fridge and stove-----------> 5*16*12=960 in
b) fridge and sink-------------> 10*16*12=1920 in
c) sink and stove--------------> 15*16*12=2880 in
</span><span>then add, 960 + 1920 + 2880 = 5760 in
</span>
<span>the answer asks for the distance in 18 in lengths
so divide 5760 by 18 -------------> 5760/18=320 
</span><span>
the answer part N 5) is 320 </span>eighteen-inch steps

6. The distance covered by the cook in Triangle A equals 
a) fridge and stove-----------> 5*15*12=900 in
b) fridge and sink-------------> 10*22*12=2640 in
c) sink and stove--------------> 15*15*12=2700 in
then add, 900 + 2640 + 2700 = 6240 in

the answer asks for the distance in 18 in lengths 
so divide 6240 by 18 -------------> 6240/18=346.67------> 347

the answer part N 6) is 347 eighteen-inch steps<span>

</span>
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Answer:

The value of the test statistic is z = 1.39.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

Step-by-step explanation:

Using traditional methods it takes 92 hours to receive an advanced flying license.

This means that at the null hypothesis, it is tested if the mean is of 92, that is:

H_0: \mu = 92

Test if there is evidence that the technique lengthens the training time

At the alternative hypothesis, it is tested if the mean is more than 92, that is:

H_1: \mu > 92

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

92 is tested at the null hypothesis:

This means that \mu = 92

A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.

This means that n = 70, X = 93, \sigma = \sqrt{36} = 6

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{93 - 92}{\frac{6}{\sqrt{70}}}

z = 1.39

The value of the test statistic is z = 1.39.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.

Looking at the z-table, z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

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ratelena [41]

Answer:

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Step-by-step explanation:

The first step is always to look at the question to see what you are given and what you are asked for. The next step is to identify the relevant relations between what you have and what you need to find.

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1) You are given a sequence of (x, y) points where x increases by 1 from one point to the next, and y increases by a factor of 8. This tells you the value of y form a geometric sequence that is described by an exponential function.

The general form of the n-th term of a geometric sequence is ...

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If this were a geometric sequence, we could write the general term using a1=1 and r=8:

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