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olya-2409 [2.1K]
3 years ago
5

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 5 large boxes and 6 small boxes has a t

otal weight of 187 kilograms. A delivery of 3 large boxes and 2 small boxes has a total weight of 87 kilograms. How much does each type of box weigh? pls help!!!
Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:

  • large: 18.5 kg
  • small: 15.75 kg

Step-by-step explanation:

Let b and s represent the weights of the big and small boxes, respectively. Then the two delivered weights can be summarized as ...

  5b +6s = 187

  3b +2s = 87

We can eliminate the "s" variable by subtracting the first equation from 3 times the second:

  3(3b +2s) -(5b +6s) = 3(87) -(187)

  4b = 74 . . . . . collect terms

  b = 18.5 . . . . . divide by 4

Using this value in the second equation, we find ...

  3(18.5) +2s = 87

  2s = 31.5 . . . . . . . . subtract 55.5

  s = 15.75 . . . . . . . . divide by 2

The large box weighs 18.5 kg; the small box weighs 15.75 kg.

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Answer:

0.85 pounds

Step-by-step explanation:

1080 foot cable = 307 pounds

36 inches/2.9999988ft = (2.9999988 x 307) / 1080 = 920.9996316/1080 = 0.85277743666 pounds ≈ 0.85 pounds

1 inch = 0.0833333 ft

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Step-by-step explanation:

Well, let us call longer side b, shorter side a and diagonal d. The perimeter of a rectangle is 2*(a+b). Let us write this formula as P=2*(a+b)

In (1) it is stated that b=a+2. Hence, the perimeter of the rectangle is P=2*(a+b). In terms of b, let us write (a+2). So P=2*(a+a+2)=4a+4.

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Therefore the answer is indeed 1.95$.

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