All categories

2 years ago

PLZ HELP!!!!! Which of these quadrilaterals can always be classified as a rhombus? A) kite

Mathematics

1 answer:

zaharov [31]2 years ago

3 0

Answer:

A) Kite

A rhombus is a simply a diamond. Think about the visual properties of a diamond. Isn't a kite a diamond?

You might be interested in

In 2009, Zane paid $9,540 in federal income tax. In 2010, he paid 10% less. How much did Zane pay in 2010?

Dominik [7]

Answer: $940

Step-by-step explanation:

You multiply the 9540 by .10 because 10% turns into .10 and then when you multiply that which is.... 9540x.10= 954

4 0

3 years ago

Read 2 more answers

Need answer please !!

Misha Larkins [42]

Answer:

Step-by-step explanation:

Least common denominator is 10

there are 10/10 portions in the whole circle

1/2 = 5/10

2/5 = 4/10

10/10 - 5/10 - 4/10 = 1/10

3 0

2 years ago

Use the function to fill in the blanks in the table.

S_A_V [24]

Answer:

gnrg

Step-by-step explanation:

5 0

3 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Which of the following is not a kind of consumer credit? a. installment credit b. personal loans c. service credit d. marginal c

Nat2105 [25]

A) installment credit
B ) personal loan
C) service credit
D) marginal credit

7 0

3 years ago

Read 2 more answers