v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
The equation of the line in this graph is y = 3/2x + 3.
Explanation:
In slope intercept form equations, the initial value is where everything begins. In this equation, that would be at the point (0,3). From there, because it is going up toward the right side, there is a positive slope. The formula for slope is rise over run, so to get our slope, we have to go up 3 units and over 2 units.
The answer is 3.1428 (very close to π actually lol)
