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gtnhenbr [62]
2 years ago
7

A total of 100 students play on the Sports Academy’s soccer, track, or basketball teams. No student plays on more than one team.

61 of the students are boys. There are 36 students on soccer teams, 19 are on the girls’ soccer team. There are 35 students on basketball teams, 18 are on the boys’ basketball team. How many boys are on the track team? please hurry and help me
Mathematics
2 answers:
Westkost [7]2 years ago
7 0

Answer:

I'm 100% sure its 26

Step-by-step explanation:

Lmk if its right and trust me ;)

d1i1m1o1n [39]2 years ago
4 0

26 is the answer

Hope this helped

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Evaluate the geometric series. Round to the nearest hundredth. Please help me!!!
kari74 [83]

Answer:

62.34

Step-by-step explanation:

Substitute n = 0 to n = 5 into the expression and sum the terms, that is

3 [ (\frac{3}{2}) ^{0}  + (\frac{3}{2}) ^{1} + (\frac{3}{2}) ^{2} + (\frac{3}{2}) ^{3} + (\frac{3}{2}) ^{4} + (\frac{3}{2}) ^{5} ]

= 3 [ 1 + \frac{3}{2} + \frac{9}{4} + \frac{27}{8} + \frac{81}{16} + \frac{243}{32} ]

= 3( \frac{665}{32} )

= 3 × 20.781

= 62.34 ( to the nearest hundredth )

5 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0
3 years ago
Complete the square to solve the equation below. <br> Check all that apply.<br> x^2-10x-4=10
fomenos

1. Move terms to the left side

2.Subtract the numbers

3.Use the quadratic formula

4.Simplify

5.Separate the equations

6.Solve

Rearrange and isolate the variable to find each solution.

Solution,

Solution

x=5±√39

7 0
2 years ago
Is a the correct answer ? Or which one
Aleonysh [2.5K]

Answer:

A is correct.

Step-by-step explanation:

Plug the 12 books he bought into the equation. Then, multiply 2.25 and 12, and that's your answer. Hope this helps. Please mark Brainliest! :)

6 0
3 years ago
ALGEBRA! NEED HELP!
Nimfa-mama [501]
Since each edge's length is x, each face's are would be { x }^{ 2 }
And cubes have 6 faces. multiply 6 by { x }^{ 2 }, the formula is :6{ x }^{ 2 }
7 0
3 years ago
Read 2 more answers
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