Answer:
x=5, y=41
Step-by-step explanation:
Because both equations are equal to Y, you can set them equal to each other like this:
8x+1=3x+26
From here, solve for x:
1. 5x+1=26
2. 5x=25
3. x=5
Once you have x, plug it back in to one of the original equations:
y=8(5)+1
y=41 and then you have your answer
If this answer was particularly helpful, please feel free to give it brainliest!! I would greatly appreciate it.
The function (119x + 171) represents the amount, in dollars. Lionel will save 409 $ if he uses Quality Electric for a repair needing 2 hours of labor.
<h3>What is a system of equations?</h3>
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
The system of equations are;
p(x) = 68x + 81.
q(x) = 51x + 90.
So,
p(x) + q(x) = 68x + 81 + 51x + 90
p(x) + q(x) = 119x + 171
The function (119x + 171) represents the amount, in dollars, Lionel will save by having Quality Electric handle an x-hour repair instead of Phil’s Appliances.
p(x) + q(x) = 119x + 171
x= 2 hours
p(x) + q(x) = 119 (2) + 171
p(x) + q(x) = 409
Lionel will save 409 $ if he uses Quality Electric for a repair needing 2 hours of labor.
Learn more about equations here;
brainly.com/question/10413253
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Answer:
The probability that Karen has bought at least one dented can is 82.5%
Step-by-step explanation:
To know the probability of Karen buying at least one dented can, it's easier to calculate the probability of her not buying any dented can, and we know that:
The probability of a can not being dented is (in the same principle as above, 100%(all cans)-7%(dented cans)=93%(non-dented cans) 0.93.
As the probability of a can being dented or not is independent from each other, we multiply the probabilities:
Now, we calculate the probability of at least one dented can, expressed as a percentage:
Answer: 36
Step-by-step explanation:
To find out the score, you would divide the total number of points (40) by 100 and then times it by the percentage you want (90).
Hope this helps :)
