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3 years ago

Moving a magnet inside a coil of wire will induce a voltage in the coil. How is the voltage in the coil increased?

Physics

2 answers:

Kisachek [45]3 years ago

6 0

I believe it's B, i'm not 100% sure tho

hoa [83]3 years ago

5 0

Answer:

Move the magnet inside the coil of wire more rapidly.

Explanation:

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When perspiration on the human body absorbs heat, some of the perspiration turns into water vapor?

bixtya [17]

Yes, this statement is true. Majority of the fluids in our body is water. So, when we perspire, it comes out as a salt solution. When the water vaporizes and turns into water vapor, it leaves white residues in our garments after a while. The salt can't be vaporized as fast as the water so it is left as a solid.

3 0

3 years ago

What is the pressure inside such a balloon (in atm) if it starts out at sea level with a temperature of 12.8°C and rises to an a

tatiyna

Answer:

The final pressure inside the balloon will be $P_2=0.0359\ atm$ .

Explanation:

Given initial temperature of the balloon is $T_1=12.8\°C$

And the final temperature of the balloon is $T_2=-47.7\°C$

Initially, the balloon is at atmospheric pressure $P_1=1\ atm$ and volume be $V_1$

And the final pressure in the balloon is $P_2$ and the volume be $V_2$

Also, it is given in the question that the final volume became twenty-two times the original volume.

We can write $V_2=22V_1$

Now, using ideal gas equation.

$\frac{P_2V_2}{P_1V_1}=\frac{nRT_2}{nRT_2}$

Where, $R$ is the gas constant. And $n$ is moles of substance inside the balloon.

In our problem the value of $n$ will be the same for both cases. Also, $R$ is the gas constant.

$\frac{P_2V_2}{P_1V_1}=\frac{T_2}{T_1}$

Also, we have $V_2=22V_1$ from the question.

$\frac{P_2\times 22V_1}{P_1V_1}=\frac{T_2}{T_1}\\\\\frac{P_2\times 22}{P_1}=\frac{T_2}{T_1}$

We need to convert the temperature from $\°C$ to Kelvin.

$T_1=12.8\°C\\T_1=12.8+273.15=285.95\\T_2=-47.7\°C\\T_2=-47.7+273.15=225.45$

Plug these values we get,

$\frac{P_2\times 22}{1}=\frac{225.45}{285.95}\\\\22\times P_2=0.789\\P_2=\frac{0.789}{22}\\P_2=0.0359\ atm.$

So, the final pressure inside the balloon will be $P_2=0.0359\ atm$ .

6 0

3 years ago

Let r denote the distance between the center of the earth and the center of the moon. What is the magnitude of the acceleration

stepan [7]

Answer:

The magnitude of the acceleration ae of the earth due to the gravitational pull of the moon is $\mathbf{3.3187\times10^{-5}}\frac{m}{s^{2}}$

Explanation:

By Newton's gravitational law, the magnitude of the gravitational force between two objects is:

$F=G\frac{Mm}{r^{2}}$ (1)

With G the gravitational constant, M the mass of earth, m the mass of the moon and r the distance between the moon and the earth, a quick search on physics books or internet websites give us the values:

$M=5.972\times10^{24}\,kg$