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Svetach [21]
3 years ago
9

In compressed state, a spring 3.00 meters long hanging from the ceiling has a potential energy of 2.0 joules. If the entire pote

ntial energy is used to release a ball of mass 1.2 kilograms vertically downward, then what is the kinetic energy of the ball when it reaches the ground?
a) 1.2 joules
b)4.9 joules
c)2.0 joules
d)6.8 joules
Physics
1 answer:
Tanya [424]3 years ago
3 0
The correct option is: Option (C) 2.0 Joules.

Explanation:

According to law of conservation of Energy:

Initial Energy = Final Energy
KE(initial) + PE(initial) = KE(final) + PE(final) --- (1)


When in the compressed state:
KE(initial) = Initial Kinetic Energy = 0
PE(initial) = Initial Potential Energy = 2.0 J

At ground (since height is 0 with respect to ground)
KE(final) = Final Kinetic Energy
PE(final) = Final Potential Energy = 0.0 J

Plug all in (1):
(1) => KE(final) = 2.0 J (Option C)
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Answer:

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Explanation:

The density formula: φ = \frac{m}{V}

I know the mass "m", I need to find out the volume of the cylinder (V)

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Now I can find out the density (φ)

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Finally, specific gravity (Gs) is the ratio between the density of a substance (oil) "φ(o)" and the density of water "φ(w)" :

Gs = φ(o) /  φ(w)

(φ(w) = 1 Kg/L

Hope this can help you !!

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